Ask question

Ask question

All categories

2 years ago

15

The diagram is not drawn to scale

1 answer:

Firlakuza [10]2 years ago

6 0

Answer:

<h2 /><h3><em><u>3x-2 = 25 </u></em></h3><h3><em><u> 3x = 25+2 </u></em></h3><h3><em><u> 3x = 27</u></em></h3><h3><em><u> x =9</u></em></h3><h3><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>option</u></em><em><u> </u></em><em><u>c</u></em></h3>

You might be interested in

Which of the following is true about graphing polynomial functions?

igomit [66]

The answer is C, Ik this bc I already finished learning this

7 0

3 years ago

Roger wants to carpet a rectangular room with length of 8 3/4 feet and a width of 9 1/3 feet. If he has 85 square feet of carpet

Dima020 [189]

Answer:

12.66 $ft^2$

Step-by-step explanation:

Given the dimensions of the room are $8\frac{3}{4}$ = $\frac{31}{4}$ and $9\frac{1}{3}$ = $\frac{28}{3}$ .

The area of the room = $length*width$

Area= $\frac{31}{4} *\frac{28}{3}$

Area=72.33 $ft^2$

The area of the carpet=85 $ft^2$

The area of carpet left= Total area of carpet - the area of the room

The area of carpet left= 85-72.33=12.66 $ft^2$

7 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

8x42+3x59-62=n. What does "n" equal?

vitfil [10]

Answer: n=451 8*42+3*59-62=n 336+177-62=n 451=n n=451

6 0

3 years ago

A quick quiz consists of a multiple-choice question with 4 possible answers followed by a multiple-choice question with 3 possib

olga55 [171]

Answer:

0.0825

Step-by-step explanation:

1/4x1/3=0.0825

7 0

3 years ago