All categories

2 years ago

Find the base of y = b^x that contains the point (3/2, 27)

Mathematics

1 answer:

Leona [35]2 years ago

8 0

Answer:

D) b = 9

Step-by-step explanation:

Given function:

y = b^x

The graph of it should contain the point (3/2, 27)

Substitute the values and verify answer choices:

A) b= 3/2

27 = (3/2)^(3/2), False as the right side is irrational

B) b= 27

27 = 27^(3/2), False as 27^1 ≠ 27^(3/2), because 1 ≠ 3/2

C) b= x/y

27 = (x/y)^(3/2), False as is doesn't make sense

D) b= 9

27 = 9^(3/2)
27 = (3^2)^(3/2)
27 = 3^(2*3/2)
27 = 3^3
27 = 27

You might be interested in

Find the polynomial f(x) of degree 5 that has the following zeros -3(mulitiplicity 2),5,8,-7

noname [10]

Answer:

Step-by-step explanation:

(x + 3)²(x - 5)(x - 8)(x + 7)

4 0

2 years ago

Larry Lazy purchased a one year membership at a local fitness center at the beginning of the year. It cost him $150. He goes twi

Papessa [141]

$4.05 per visit
if he continued going to the gym twice a week all year would be $2.88 per visit.

7 0

3 years ago

Read 2 more answers

Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)

Klio2033 [76]

Answer:

$(g\circ h)(x)=-x^2-x-3$

Step-by-step explanation:

So we have the two functions:

$g(x)=-x-3\text{ and } h(x)=x^2+x$

And we want to find:

$(g\circ h)(x)$

This is the same thing as:

$=g(h(x))$

So, substitute h(x) into g(x):

$g(x)=-x-3\\g(h(x))=-(x^2+x)-3$

Distribute the negative:

$g(h(x))=-x^2-x-3$

And we're done!

So:

$(g\circ h)(x)=-x^2-x-3$

6 0

3 years ago

Read 2 more answers

A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 84 inches. (A

Kisachek [45]

Answer:

A. 14x14x28

B. The maximum volume is 5488 cuibic inches

Step-by-step explanation:

The problem states that the box has square ends, so you can express volume with:

$v=x^{2} y$

Using the restriction stated in the problem to get another equation you can substitute in the one above:

$4x+y=84\\\\$

Substituting y whit this equation gives:

$v=x^{2} (84-4x)\\\\v=84x^{2} -4x^{3}$

Now find the limit of x:

$\frac{84x^{2}-4x^{3}}{dx}=168x-12x^{2}\\\\x=\frac{168}{12}=14$

Find the length:

$y=84-4(14)=28$

You can now calculate the maximum volume:

$v=(14)^{2}(28)= 5488$

6 0

3 years ago

In the situation, simple interest is calculated yearly. How much interest was earned? Drag and drop the answer into the box. Pri

ad-work [718]

I = PRT
P = 8000
T = 4
R = 12%...turn to decimal...0.12
now we sub
I = (8000)(0.12)(4)
I = 3840 <==

7 0

3 years ago