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Gwar [14]
3 years ago
9

Find the volume of the figure below if the shaded (green) area is 130 square feet. What steps did you take and why?

Mathematics
1 answer:
Rudiy273 years ago
7 0

Answer:

picture is blur

Step-by-step explanation:

provide us good picture

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Find all zeros of <br>f(x)= x^3 + 3x^2 − 3x − 1
PSYCHO15rus [73]
F(1) =  1^3 + 3(1)^1 - 3 - 1 = 1 + 3 - 3 - 1 = 0

so one zero  is x = 1, and x-1 is a factor

dividing f(x)  by x - 1 gives x^2 + 4x + 1

x = [-4 +/- sqrt (16 - 4)] /  2

x = -0.27, -3.73

zeroes are 1 , -0.27 and -3.73   Answer



  
4 0
3 years ago
F(x)=6x-8<br> G(x)=-4x-7<br> Find 3f(x)-g(x)
miskamm [114]
3(6x-8)-(-4x-7)
18x-24+4x+7
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7 0
3 years ago
HELlooo PLEASE HELP TQ :_
Dmitrij [34]

Answer:

The area will be 16 units^2

Step-by-step explanation:

hope it helps you

have a great day

3 0
3 years ago
Read 2 more answers
Please help for number 25
Phantasy [73]
The correct answer is:  [C]:  " inverse variation;  xy = 40 " .
__________________________________________________
Explanation:
______________________________________________
Examine the table given, and plug in the value:
_______________________________________
In the equation for Answer choice: [C]:  " xy = 40 ".

When x = 1 , y = 40.

xy = 40 ;  1*40 = 40.  Yes.

When x = 2, y = 20.

xy = 40;  2*20 = 40.  Yes. 

When x = 5, y = 40.

xy = 40.  8* 5 = 40.  Yes.

When x = 10, y = 4.

xy = 40.  10*4 = 40. Yes.
_______________________________________
So the equation makes sense ;
 
"inverse variation;  xy = 40".
________________________________________
since; "xy = 40" ; which is "answer choice: [C]".
________________________________________
     We know that the other choices do NOT make sense; if we plug in any of the corresponding x and y values for any of the equations provided in any of the other answer choices, the equations will not equal, and as such, the answer choices are incorrect.
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8 0
3 years ago
What is the maximum vertical distance between the line y = x 30 and the parabola y = x2 for −5 ≤ x ≤ 6?
Arlecino [84]
Set y1=x+30 and y2=x^2, plugged those into the distance formula assuming x=a<span>, 
</span><span>
d=rad(<span>(y2−y1<span>)^2)
</span></span></span><span>d(x)=x^2−x−30

</span>All you have to do is to maximize the given quadratic function. I hope that this is the answer that you were looking for and it has helped you.
7 0
3 years ago
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