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GalinKa [24]
2 years ago
7

A 12 ounce Starbucks latte costs $3.36. What is the constant of proportionality that relates the cost in dollars, y, to the numb

er of ounces, x, in a Starbucks latte?
Mathematics
2 answers:
bazaltina [42]2 years ago
5 0

Answer:

Y = X times 0.28

Step-by-step explanation:

1. You set it up as a proportionality

12/1 and 3.36/x

The x stands for how much money it takes to get 1 ounce

2. You do the old man line.

12 times x = 3.36 times 1

12x = 3.36

3. Now you divide 3.36 by 12

3.36 divided by 12

.28

4. You insert 0.28 into the problem

12 times 0.28 = 3.36

X = 0.28

So 1 ounce costs $0.28

So Y = X times 0.28

Andrej [43]2 years ago
5 0

Answer:

Step-by-step explanation:

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3 years ago
Which statement would be true if you evaluate the expression (560x70) ÷10
Marat540 [252]

Answer:

none

Step-by-step explanation:

No choice is correct.

The original expression has 560 x 70, the product of 560 and 70 inside the parentheses.

(560 x 70) ÷ 10 is 10 times smaller than 560 x 70

None of the choices show 560 x 70. They show 560 + 70 and 560 - 70.

Answer: none

8 0
2 years ago
Joe plans to buy a pair of golf shoes. The original price of the pair Joe wants is $75, but they are now on sale for 20% off. Wh
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2 years ago
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Sveta_85 [38]

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Step-by-step explanation:

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5 0
2 years ago
What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator
kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

                                          = 10!

                                          = 10*9*8*7*6*5*4*3*2*1

                                          = 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of  L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are  

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

  =  10! / (2! 2! 2 !)  

  = 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

  = 3628800 / 2 * 2 * 2

  =  3628800 / 8

  =   453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

 1 / total number of different permutations  

= 1 / 10! / (2! 2! 2 !)  

= 1/453600

= 0.000002

8 0
3 years ago
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