the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
11.35%
Step-by-step explanation:
Add all of the numbers together to get the total amount of people who visited.
Add all the numbers in the teen section to find how many teens visited.
If you put teens over whole it will give you the fraction 86/758
If you divide 86 by 758 you will get 0.11345646438
.
Move the decimal two places to the right and round to get the percent 11.35.
360/18=20
So, your answer is 20 unit rate.
Hope this will help you!
The larger value is 9 x 10^9
The smaller value is 3 x 10^(-4)
Divide the larger over the smaller
Doing so will have you divide the coefficients 9 and 3 (numbers in front of the "times ten to the..." portions) to get 9/3 = 3.
Then you'll also subtract the exponents: 9 minus (-4) = 9 - (-4) = 9 + 4 = 13
In summary so far, we got a coefficient of 3 and an exponent of 13
So the final answer is 3 x 10^13 (assuming you want scientific notation)
If you want to convert to standard notation, instead of scientific notation, move the decimal point in 3.0 thirteen spots to the right to get
30,000,000,000,000
there are 13 zeros (four groups of 3 plus one just after the 3) in that value above. This is the number 30 trillion
Answer:
11i-6
Step-by-step explanation: