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2 years ago

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Mathematics

1 answer:

Bad White [126]2 years ago

6 0

The net would be 51 feet long to stretch from one side of the court to the other

<h3>What are scaled drawings?</h3>

Scale drawings are drawings that shows a diagram with another proportional dimensions

The scale ratio of the diagram is given as:

Scale = 1 inch = 12 feet

The length of the net is given as:

Length = 4.25 inches

So, the actual length of the net is:

$Length = 4.25 \times 12$

Evaluate the product

$Length = 51$

Hence, the net would be 51 feet long, if stretched across the court

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. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar

yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total 4+5+6 = 15 bulbs. If we want to select 3 randomly there are K ways of doing this, where K is the combination of 15 elements taken 3 at a time

$K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455$

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

$\frac{270}{455}=0.5934=59.34\%$

(b)

The probability of selecting three 40-W bulbs is

$\frac{4*3*2}{455}=0.0527=5.27\%$

The probability of selecting three 60-W bulbs is

$\frac{5*4*3}{455}=0.1318=13.18\%$

The probability of selecting three 75-W bulbs is

$\frac{6*5*4}{455}=0.2637=26.37\%$

Since the events are disjoint, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

$\frac{6*5*4}{455}=0.2637=26.37\%$

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, supposing there is no replacement, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is $\frac{9}{15}=0.6$

Since there are no replacement, the probability of taking a second non 75-W bulb is now $\frac{8}{14}=0.5714$

Following this procedure 5 times, we find the probabilities

$\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}$

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0

3 years ago

Sofia jarred 18 liters of jam after 6 days. How many days does Sofia need to spend making jam if she wants to jar 30 liters of j

Novay_Z [31]

Answer:

10 Days

Step-by-step explanation:

First u need to find out how many liters of jam she made every day so you have to do 18 divided by 6 = 3, she made 3 jams each day. The question is asking how much days she needs to make 30 liters of Jam so divided 30 by 3 and u will get your answer which is 10

6 0

3 years ago

Which fraction is the smallest? A. 5⁄6 B. 2⁄3 C. 3⁄5 D. 11⁄15

BabaBlast [244]

Answer:

Step-by-step explanation:

5/6=0.83

2/3=0.66

3/5=0.60

11/15=0.73

by changing them to a decimal you get a better look at the amounts they are work and it puts them in a common value.From this you can see that 3/5 is the lowest fraction form the groups so your answer would be C

6 0

3 years ago

Read 2 more answers

A robot can complete 4 tasks in 5/6

atroni [7]

I am the goddes of the air pods and the books of the laptops

4 0

3 years ago

PLEASE HELP ME OUT..........

Vlad1618 [11]

Here is your answer

$\bold{x=12}$

REASON:

$Concept used$ : The opposite sides of a parallelogram are equal.

So, in above given figure

$3x+7=5x-17$ (measures of opposite sides)

$5x-3x= 17+7$

$2x= 24$

$x= 24/2$

$x= 12$

HOPE IT IS USEFUL

6 0

3 years ago

Read 2 more answers