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2 years ago

Hey y’all can u please give me the correct answer.

Mathematics

1 answer:

ANEK [815]2 years ago

7 0

Step-by-step explanation:

-8 - 6x < 1

Bringing like terms on one side

-6x < 1 + 8

-6x < 9

x < 9/-6

x < 3/-2

I think the correct answer is none

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Which expression is equivalent to

KonstantinChe [14]

Given the expression:

$\sqrt[4]{ \frac{24x^{6}y}{128x^{4}y^{5}}}$

Simplifying:

$\sqrt[4]{ \frac{3x^{2}}{16y^{4}}}$

Then the answer is:

$\frac{ \sqrt[4]{3x^{2}}}{2y}$

6 0

3 years ago

Given points A (-3,-4) and B (2,0), points P (-1,-12/5) partitions line AB in the ratio

kvv77 [185]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&A&(~ -3 &,& -4~) 
&P&(~ -1 &,& -\frac{12}{5}~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AP=\sqrt{[-1-(-3)]^2+[-\frac{12}{5}-(-4)]^2}
\\\\\\
AP=\sqrt{(-1+3)^2+(-\frac{12}{5}+4)^2}\implies AP=\sqrt{2^2+\left( \frac{8}{5} \right)^2}
\\\\\\
AP=\sqrt{4+\frac{64}{25}}\implies AP=\sqrt{\cfrac{164}{25}}\implies AP=\cfrac{\sqrt{164}}{\sqrt{25}}
\\\\\\
\boxed{AP=\cfrac{2\sqrt{41}}{5}}$

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&P&(~ -1 &,& -\frac{12}{5}~) 
&B&(~ 2 &,& 0~)
\end{array}
\\\\\\
PB=\sqrt{[2-(-1)]^2+[0-\left(-\frac{12}{5} \right)]^2}
\\\\\\
PB=\sqrt{(2+1)^2+\left( \frac{12}{5} \right)^2}\implies PB=\sqrt{9+\frac{144}{25}}\implies PB=\sqrt{\cfrac{369}{25}}
\\\\\\
PB=\cfrac{\sqrt{369}}{\sqrt{25}}\implies \boxed{PB=\cfrac{3\sqrt{41}}{5}}$

so, let's check the ratio of AP:PB

$\bf AP:PB\implies \cfrac{AP}{PB}\implies \cfrac{\frac{2\sqrt{41}}{5}}{\frac{3\sqrt{41}}{5}}\implies \cfrac{2\underline{\sqrt{41}}}{\underline{5}}\cdot \cfrac{\underline{5}}{3\underline{\sqrt{41}}}\implies \cfrac{2}{3}$

7 0

3 years ago

Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran

anastassius [24]

(x; y) -> (x - 2; y + 4)

J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)

K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)

L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)

M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)

5 0

3 years ago

Evaluate the expression w+9 when w=1

Paladinen [302]

Answer:

= 10

Step-by-step explanation:

w + 9

if, w = 1

SO...

1 + 9 = 10

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2 years ago

Use the discriminant to determine the nature of the roots of the following equation.

kvv77 [185]

Discussion

The discriminate is b^2 - 4*a*c

The general equation for a quadratic is ax^2 + bx + c

In this equation's case

a = 1

b= -5

c = - 3

Solve

(-5)^2 - 4*(1)*(-3)

25 - (-12)

25 + 12

Note

Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.

4 0

3 years ago