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andre [41]
3 years ago
8

You should type using

Computers and Technology
1 answer:
vovikov84 [41]3 years ago
8 0

b. slow down and in strokes

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Look at the following description of a problem domain:The bank offers the following types of accounts to its customers: saving a
Alchen [17]

Answer:

The answers are explained below

Explanation:

1) Identify the potential classes in this problem domain be list all the nouns

class Customer

class Acco  unt

2) Refine the list to include only the necessary class names for this problem

the class customer is not necessary to solve the problem itself, therefore the only class could be the account class

3) Identify the responsibilities of the class or classes.

The responsibilities of the class account will be

* determination of the type of account--> Acc  ount . type(char)

*  deposit money into the account --> Acc  ount . de posit(float)

* withdraw money into the account --> Acc  ount . with draw(float)

* show balance of the account --> Acc  ount . bal ance()

* generate interest --> Acc  ount . int erest()

Please join the words together. I used spaces due to regulations

5 0
4 years ago
Write a program in C++ to Find the Average of the sum of prime numbers between 1 to any given number
mixas84 [53]

Using the knowledge in computational language in C++ it is possible to write a code that Find the Average of the sum of prime numbers between 1 to any given number

<h3>Writting in C++ code:</h3>

<em />

<em>#include <iostream></em>

<em>using namespace std;</em>

<em>bool isPrime(int n){</em>

<em>   for(int i = 2; i < n/2; i++){</em>

<em>      if(n%i == 0){</em>

<em>         return false;</em>

<em>      }</em>

<em>   }</em>

<em>   return true;</em>

<em>}</em>

<em>int findPrimeSum(int n){</em>

<em>   int sumVal = 0;</em>

<em>   for(float i = 2; i <= n; i++){</em>

<em>      if(isPrime(i))</em>

<em>         sumVal += i;</em>

<em>   }</em>

<em>   return sumVal;</em>

<em>}</em>

<em>int main(){</em>

<em>   int n = 15;</em>

<em>   cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>

<em>   return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

8 0
1 year ago
Consider the following code segment. int[][] arr = {{3, 2, 1}, {4, 3, 5}}; for (int row = 0; row &lt; arr.length; row++) { for (
ludmilkaskok [199]

Answer:

Condition one - 1 time

Condition two - 2 times

Explanation:

Given

The above code segment

Required

Determine the number of times each print statement is executed

For condition one:

The if condition required to print the statement is:  <em>if (arr[row][col] >= arr[row][col - 1]) </em>

<em />

For the given data array, this condition is true only once, when

row = 1  and  col = 2

i.e.

<em>if(arr[row][col] >= arr[row][col - 1]) </em>

=> <em>arr[1][2] >= arr[1][2 - 1]</em>

=> <em>arr[1][2] >= arr[1][1]</em>

<em>=> 5 >= 3 ---- True</em>

<em />

The statement is false for other elements of the array

Hence, Condition one is printed once

<em />

<em />

For condition two:

The if condition required to print the statement is:  <em>if (arr[row][col] % 2 == 0) </em>

<em />

The condition checks if the array element is divisible by 2.

For the given data array, this condition is true only two times, when

row = 0  and  col = 1

row = 1  and  col = 0

i.e.

<em>if (arr[row][col] % 2 == 0) </em>

<em>When </em>row = 0  and  col = 1

<em>=>arr[0][1] % 2 == 0</em>

<em>=>2 % 2 == 0 --- True</em>

<em />

<em>When </em>row = 1  and  col = 0

<em>=>arr[1][0] % 2 == 0</em>

<em>=> 4 % 2 == 0 --- True</em>

<em />

<em />

The statement is false for other elements of the array

Hence, Condition two is printed twice

3 0
3 years ago
There are three required elements needed to connect to the internet: hardware, web browser, and __________.
malfutka [58]

Yes the answer is D.internet service.

7 0
3 years ago
Read 2 more answers
Your auto insurance policy has a $200 monthly premium and $700 deductible. what is the maximum amount you will have to pay out o
saul85 [17]
Your monthly premium is the payment you make to your car insurance company that keeps your coverage active.

A car insurance deductible is the amount of money you have to pay toward repairs before your insurance covers the rest.

Therefore $700 is the maximum amount you will have to pay
<span>out of pocket for a car accident before your insurance covers your cost.</span>
4 0
3 years ago
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