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3 years ago

Help me rickroll you

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

5 0

Answer:

Shoyo here!

Step-by-step explanation:

wow.

Gennadij [26K]3 years ago

3 0

Answer:

Never Gonna Give You Up ♩ ♪ ♫ ♬

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Use the list method to write "the perfect square integers between 1 and 80 inclusive".

Len [333]

<span> all of our square numbers from 1 to 80 are 1, 4, 9, 16, 25, 36, 49, 64. </span>

5 0

3 years ago

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Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

PLEASE ANSWER THIS IS REALLY IMPORTANT!!!

Elan Coil [88]

Answer: C
Explanation: The y-intercept which is -9 matches with the equation and the slope matches too

4 0

3 years ago

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The area of a triangular flower bed in the park has an area of

blagie [28]

Answer:

b = 24 ft

h = 10 ft

Step-by-step explanation:

120 = ½hb

120 = ½h(3h - 6)

240 = h(3h - 6)

240 = 3h² - 6h

80 = h² - 2h

0 = h² - 2h - 80

0 = (h - 10)(h + 8)

h = 10 ft or -8 ft

we ignore -8 as it makes no sense for a triangle side length.

b = 3(10) - 6 = 24 ft

8 0

2 years ago

Which pair of inequalities would overlap if they were graphed?

Fittoniya [83]

Answer:

x <= 10, x >4

Step-by-step explanation:

This is because 4 is less than 10 and 10 is greater than 4, making them overlap

4 0

3 years ago