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Bumek [7]
3 years ago
7

If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)

Mathematics
1 answer:
Elden [556K]3 years ago
5 0
To solve this problem you must apply the proccedure shown below:
 1. You have the following functions given in the problem above:
 f(x)=x-6 &#10; and g(x)=x1/2(x+3)=x(x+3)/2<span>
 2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
 </span>g(x)*f(x)=(x-6)*x(x+3)/2<span>
 3. Applying the distributive property, you have:
</span> g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2
 g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2
 The answer is:  g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2
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we are given

r(t)=(7t,3cos(t),3sin(t))

we can find x , y and z

x=7t,y=3cos(t),z=3sin(t))

now, we can use arc length formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

now, we can find derivative

x'=7,y'=-3sin(t),z'=3cos(t))

now, we can plug values

and we get

L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt

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=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)

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3 years ago
Find the balance in the account. $2,500 principal earning 4%, compounded quarterly, after 4 years
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7 0
3 years ago
Compare partial products and regrouping
Stella [2.4K]

Let us first describe how partial product and regrouping are alike:

Partial Products and Regrouping are alike because both methods are multiplied by one number and if the product of the number has 2 digits it can be carried.

Now let us discuss how they are different:

Partial Products and Regrouping are different because Partial Products are doing multiplication step by step and regrouping is regular multiplication.

Hope it helps.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=7%20-%204%20%5Cfrac%7B3%7D%7B4%7D%20" id="TexFormula1" title="7 - 4 \frac{3}{4} " alt="7 - 4 \
AlladinOne [14]

7 - 4 3/4

= 28/4 - 19/4 = 9/4

Answer is 2 1/4 or 2.25.

5 0
3 years ago
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