Question

If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)

Answer 1

To solve this problem you must apply the proccedure shown below:
 1. You have the following functions given in the problem above:
 $f(x)=x-6$ and $g(x)=x1/2(x+3)=x(x+3)/2$
 2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
 $g(x)*f(x)=(x-6)*x(x+3)/2$
 3. Applying the distributive property, you have:
 $g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2$
 $g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$
 The answer is:  $g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$