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Ahat [919]
2 years ago
10

Stan pays a 10% deposit to put a pool table on lay-by.

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
6 0

Answer:

$1431

Step-by-step explanation:

If Stan pays a 10% deposit, he pays $159. 10% of $1590 is simply 0.1 * 1590 = 159. Assuming this is the only amount he pays, he then simply needs to pay the full price minus $159. We can find this by simply subtracting 159 from 1590 to get 1431. Stan still needs to pay $1431.

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-3(y-5)+6y-2 simplify using distributive property and then combine like terms ANOTHER ONE PLEASE
posledela

Answer:

3y+13

Step-by-step explanation:

-3(y-5)+6y-2

Distribute

-3y +15 +6y-2

Combine like terms

-3y+6y  +15-2

3y            +13

3 0
3 years ago
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The midpoint of is point P at (−6,−2). If point E is at (2,−4), what are the coordinates of point F?
ipn [44]

Point F = (-2,-3); Apply the midpoint formula, (x1+x2/2),(y1+y2/2) = (x,y).

-6+2/2

-4/2

x=-2

-2+(-4)/2

-6/2

y=-3

(x,y)=(-2,-3)

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4 years ago
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Describe the translation below using words and then write a rule for it.
Triss [41]
The transformation of the figure is a translation. The original figure moves over 2 squares, then down once. The rule would be (x-2, y-1)

I’m pretty sure the answer is correct but my wording may not be so good :|
7 0
3 years ago
8×4=(A×7)-(A×3)<br>what is the value of A in the equation shown??​
Pani-rosa [81]

Answer:

Step-by-step explanation:

8×4 = (A×7) - (A×3) = A(7-3) = A×4

A = 8

4 0
3 years ago
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.
dsp73

Answer:

The required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, a_2=10,a_3=5,a_4=2.5,a_5=1.25

r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}

The common ratio of GP is 1/2.

r=\frac{a_2}{a_1}

\frac{1}{2}=\frac{10}{a_1}

a_1=20

The first term of the sequence is 20.

The formula for sequence is

a_n=a(r)^{n-1}

Where a is first term and r is common difference.

The required sequence is

a_n=20(\frac{1}{2})^{n-1}

The formula for rate of change is

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

The average rate of change from n = 1 to n = 3 is

m=\frac{f(3)-f(1)}{3-1}

m=\frac{5-20}{3-1}

m=\frac{-15}{2}=-7.5

Therefore the required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

8 0
4 years ago
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