The width of rectangular garden(b) = 8 feet and
The area of rectangular garden = 160 square feet
Step-by-step explanation:
Given,
The length of rectangular garden(l) = 20 feet and
The perimeter of rectangular garden(fencing) = 56 feet
To find, the width of rectangular garden(b) = ? and
The area of rectangular garden = ?
We know that,
The area of rectangular garden = 2(l + b)
⇒ 2(20 + b) = 56
⇒ 20 + b = 28
⇒ b = 28 - 20 = 8 feet
The width of rectangular garden(b) = 8 feet
∴ The area of rectangular garden = l × b
= 20 feet × 8 feet
= 160 square feet
Hence, the width of rectangular garden(b) = 8 feet and
the area of rectangular garden = 160 square feet
For this case we have:
Let:
x: number of points scored by Duncan
y: number of points scored by Eddie
We have:
(1)
(2)
Substituting (2) in (1):
Thus, Duncan could have scored a maximum of 62 points.
Answer:
points scored by Duncan.
9514 1404 393
Answer:
(c) $4,083.84
Step-by-step explanation:
The amount due is ...
A = P(1 +rt)
where P is the amount borrowed, r is the annual rate, and t is the number of years. For "exact interest", we use 365 days in a year, so the number of years is 90/365.
A = $4000(1 + 0.085×90/365) ≈ $4083.84
Juan's loan will have a value of $4083.84 at maturity.
Answer:
hi, im not 100% sure but i think this is false.
Step-by-step explanation:
Answer: b. It's a fair method because each result is an equally likely possible outcome.
The number of students is same as the number of the sides of the dice. In this scenario, the school principal will roll two dices three times and the number that repeated most will be chosen. For every dice, all number will have equally likely possibility so the randomization is fair(1/6 chance for every student).Rolling the dice >1 times will have a problem because there is a high chance to get draw result. It doesn't have any correlation with fairness though.
