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ololo11 [35]
2 years ago
10

I need help yall help me

Mathematics
1 answer:
irga5000 [103]2 years ago
7 0

Answer:

Step-by-step explanation:

answer is c

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The cost C (in dollars) for the care and maintenance of a horse and carriage is C=15x+2000 where x is the number of rides.
MissTica

Answer: 100 rides are needed to break even.


Step-by-step explanation:

We have given the cost function

C(x)=15x+2000 where x is the number of rides.

And rides cost 35$

⇒ revenue function would be 35 times x

i.e.R(x)=35 x , where x is the number of rides.

Break even point of a firm occurs when at a certain point x the total cost equals to the total revenue.

i.e. at break even point

total revenue=total cost

⇒35x=15x+2000

⇒35-15x=2000[subtract 15x from both sides]

⇒20x=2000 [simplify]

⇒x=2000/20[dividing both sides with 20]

⇒x=100

∴ 100  rides are needed to break even.

6 0
3 years ago
The equation of a circle in general form is ​ x2+y2+22x+14y−55=0 ​ . What is the equation of the circle in standard form?
ra1l [238]
x^2+y^2+22x+14y-55=0 \\\\x^2+22x+y^2+14y=55\\\\(x^2+22x+121)-121+(y^2+14y+49)-49=55\\\\(x+11)^2+(y+7)^2-121-49=55\\\\
(x+11)^2+(y+7)^2-170=55\\\\(x+11)^2+(y+7)^2=55+170\\\\\boxed{(x+11)^2+(y+7)^2=225}

Answer B.
4 0
2 years ago
Read 2 more answers
for the school play adult tickets cost 4$ and children tickets cost 2$ natalie is working at the ticket counter and just sold 20
lilavasa [31]
Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be

4x + 2y = 20

There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.

When x=0,
4(0) + 2y = 20
y = 10

When x=1,
4(1) + 2y = 20
y = 8

When x=2,
4(2) + 2y = 20
y = 6

When x=3,
4(3) + 2y= 20
y = 4

When x = 4,
4(4) + 2y = 20
y = 2

When x = 5,
4(5) + 2y = 20
y = 0

When x = 6,
4(6) + 2y = 20
y = -2

A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:

   Number of adult tickets             Number of children tickets
                  0                                                   10
                  1                                                    8
                  2                                                    6
                  3                                                    4
                  4                                                    2
                  5                                                    0




6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cpi%20%20x%5E%7B2%7D%20" id="TexFormula1" title=" \pi x^{2} " alt=" \pi x^{2} " align="
ANEK [815]

The formule is about area of a circle.

\pi x^{2} = a

We need to solve the equation for x. Where x is the radius of the circle.

In order to solve it for x, we need isolate it for x on left side.

So, first we need to get rid pi from left side.

On dividing both sides by pi, we get

\frac{\pi x^2}\pi}=\frac{a}{\pi}

x^2=\frac{a}{\pi}

Taking square root on both sides, we get

\sqrt{x^2}=\sqrt{\frac{a}{\pi}}

x=\sqrt{\frac{a}{\pi}}


4 0
3 years ago
Suppose you draw a card from a​ well-shuffled deck of 52 cards. What is the probability of drawing a 5 or a queen?
goldfiish [28.3K]
A 5 or a queen

52 cards per deck
each card repeats 4 times

a 5 or a queen
there are four 5's and four queens
4+4=8

probablity=desiredoutcomes/totalpossible
probablity=8/52
probablity=4/26
probablity=2/13
5 0
3 years ago
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