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3 years ago

How many degrees is 1/4 of a circle?

Mathematics

2 answers:

irina1246 [14]3 years ago

5 0

45 degrees is the answer to your problem

ikadub [295]3 years ago

4 0

A 90 degrees turn is one fourth of the circle

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The diagram shows a sector of a circle of radius 4 cm.<br> work out the length of the arc abc

Zielflug [23.3K]

Need to know the angle for this I think?

3 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago

(2x-3)(4-3x) Find the product of the binomials

kobusy [5.1K]

(2X-3)(4-3X)
=8X-6X²-12+9X
=-6X²+17X-12
That's your answer.

7 0

3 years ago

Read 2 more answers

P + nx=rx-e (solve for x)

lorasvet [3.4K]

Answer:

(p+e)/(r-n) = x

Step-by-step explanation:

p + nx=rx-e

Add e to each side

p +e+ nx=rx-e+e

p +e+ nx=rx

Subtract nx from each side

p +e+ nx - nx=rx-nx

p+e = rx -nx

Factor out x

p+e = x(r-n)

Divide each side by (r-n)

(p+e)/(r-n) = x(r-n)/(r-n)

(p+e)/(r-n) = x

8 0

3 years ago

Determine the sampling error if the grade point averages for 10 randomly selected students from a class of 125 students has a me

zaharov [31]

The sampling error if the grade point averages for 10 randomly selected students from a class of 125 students has a mean of x =2. is A. -0.7.

Given:

Random number=10

mean of x=2

population=125

mean of p=2.7

Using this formula

Sampling error=x− μ

Where:

x= sample mean=2

μ=population mean=2.7

Let plug in the formula

Sampling error=2-2.7

Sampling error=-0.7

Inconclusion the sampling error is A.-0.7.

Learn more here:

brainly.com/question/13929265

3 0

2 years ago