So first you would set up the equation of 48 = x + x + 3(2)x + 3(2)x. Perimeter is equal to width + width + length + length-- x is width, length is 3 times 2x, so that's where that equation comes from. You combine like terms and get 48 = 2x + 6x + 6x or 48 = 14x. You then divide by 14 and get x ≈ 3.4. Then to find the dimensions you substitute it back to what I said the dimensions were. Width is x, so width is around 3.4. Length is 3 times twice the width (x) so 3(2x) or 6x. So you substitute ≈3.4 for x and get ≈20.6. The width is ≈3.4 and the length is ≈20.6 (the dimensions).
The answer to the question is a
Answer:
Step-by-step explanation:
we are given as
(x, y), = (5, 10)
we can compare
x-value is 5
y-value is 10
now, we can use formula
now, we can plug values
so, we get
Answer: what grade is this
Step-by-step explanation:
Answer:
<u>The box with largest volume is Box A. Its volume of 67,375 cm³ (cubic centimeter) or 0.068 m³(cubic meter) is higher than box B and box C.</u>
Step-by-step explanation:
1. Given that we know the three dimensions (length, width and height) of each box, we will use the following formula for calculating the volume:
Volume = Length * Width * Height
Box A
Volume = Length * Width * Height
Volume = 35 * 35 * 55
Volume = 67,375 cm³
Converting to m³ = 67,375 * 10⁻⁶ = 0.068 m³ (Rounding to 3 decimal places)
Box B
Volume = Length * Width * Height
Volume = 40 * 40 * 40
Volume = 64,000 cm³
Converting to m³ = 64,000 * 10⁻⁶ = 0.064 m³ (Rounding to 3 decimal places)
Box C
Volume = Length * Width * Height
Volume = 60 * 30 * 30
Volume = 54,000 cm³
Converting to m³ = 54,000 * 10⁻⁶ = 0.054 m³ (Rounding to 3 decimal places)
<u>The box with largest volume is Box A. Its volume of 67,375 cm³ (cubic centimeter) or 0.068 m³(cubic meter) is higher than box B and box C.</u>
