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Sauron [17]
4 years ago
14

Again hellp plzzzzzzzz

Mathematics
1 answer:
charle [14.2K]4 years ago
5 0

Answer: C

Hope this helps :)

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A group of 80 students in a college are surveyed. They are asked which of Spanish or French they are studying. a) complete the V
Rudik [331]

Answer:

a) Find attached the completed Venn diagram (2nd diagram)

b) 25

c) 46

A related Question found at brainly (ID 16765143):

A group of 80 students in a college are surveyed. They are asked which of Spanish or French they are studying. 71 of the students surveyed studies at least one of the two languages.

a) Complete the Venn diagram.

b) How many students study only french?

c) How many students study Spanish?

Step-by-step explanation:

Find attached the Venn diagram (1st diagram)

a) Total number of students in college = 80

Since 71 out of the 80 students surveyed studies at least one of the two languages, the number of students that studied neither French nor Spanish = 80-71 = 9

From the venn diagram:

Number of students that study Spanish = 14

Number of students that study French = 25

We need to determine if the values are for Spanish only and French only respectively or for at least Spanish and French respectively.

Estimated value for the middle term = 80-(14+25+9) = 32

From the above calculation, the number of students that study both Spanish and French is 32 and it is more than each set value. This implies the value given in the Venn diagram is for Spanish only and French only respectively.

Let number of students that study both Spanish and French = x

Spanish only = 14

French only = 25

the number of students that studied neither French nor Spanish = 9

Total:

14 + 25 + x + 9 = 80

48 + x = 80

x = Number of students that study both Spanish and French = 32

b) French only = 25

c) Number of  students that study Spanish = students that study at least Spanish

= 14+x = 14+32

Number of  students that study Spanish = 46

5 0
3 years ago
Martha has widow's peak and attached earlobes. Martha's dad had a straight hairline and unattached earlobes. If Martha marries a
krok68 [10]

Answer:

the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%

Step-by-step explanation:

Martha = widow's peak + attached earlobes.

Martha's dad = straight hairline + unattached earlobes.

Martha husband =straight hairline+ widow's peak + attached earlobes

what is the probability that Martha child will have a widow's peak + attached earlobes?

since,

Martha + Martha husband =straight hairline+ widow's peak + attached earlobes

the probability of the child having widow peak is 2/3 = 0.6667

the probability of the child having attached earlobes is 2/3 = 0.66667

the probability of having both = 0.6667*0.66667 = 0.4445

6 0
3 years ago
What's the equation for a circle with a center of (-2, 1) and a radius of 3.​
faltersainse [42]

Answer:

(x+2)^2 + (y-1)^2 = 9

Step-by-step explanation:

The equation of a circle is written with the center and radius into the vertex form (x-h)^2 + (y-k)^2 = r^2.

Here h = -2 and k = 1. Substitute these values with r = 3.

(x--2)^2 + (y-1)^2 = 3^2\\(x+2)^2 + (y-1)^2 = 9

5 0
3 years ago
Use the quadratic formula to solve x^2 -3x - 5 = 0. Round to two decimal places.
Evgen [1.6K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}

Step-by-step explanation:

Given the equation

x^2\:-3x\:-\:5\:=\:0

solving with the quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=-5

x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}

x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{29}}{2\cdot \:1}

separating the solutions

x_1=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:1},\:x_2=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:1}

solving

x=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:\:1}

  =\frac{3+\sqrt{29}}{2\cdot \:1}

  =\frac{3+\sqrt{29}}{2}

also solving

\:x=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:\:1}

  =\frac{3-\sqrt{29}}{2\cdot \:1}

  =\frac{3-\sqrt{29}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}

7 0
3 years ago
A new car is purchased for 16900 dollars. The value of the car depreciates at 15% per year. What will the value of the car be, t
strojnjashka [21]

Answer:

 $ 11093

Step-by-step explanation:

A=25000(1+-0.15/1) <em>1(5) <-- that is supposed to be exponent</em>

A=25000(0.85)) 5 <-- supposed to be exponent

A =  11092.63

Value to nearest cent is = $11093

3 0
3 years ago
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