What are the domain and range of the function below? (In the picture)

Polynomial question,

arsen [322]

Answer:

Look at the attachment

4 0

3 years ago

For each of the following vector fields F , decide whether it is conservative or not by computing the appropriate first order pa

Mazyrski [523]

Answer:

(a)

Conservative

(b)

Not conservative

(c)

Conservative.

Step-by-step explanation:

(a)

$\mathbf{F}(x,y) = (-10x+7y,7x+6y)$

Notice that

$\frac{\partial\mathbf{F}_y}{\partial x} = 7$

and

$\frac{\partial\mathbf{F}_x}{\partial y} = 7$

Therefore the field is conservative.

(b)

Notice that

$\mathbf{F}(x,y) = (-5y,-4x)$

and

$\frac{\partial\mathbf{F}_y}{\partial x} = -4$

but

$\frac{\partial\mathbf{F}_x}{\partial y} = -5$

Therefore is not conservative.

(c)

Notice that

To prove that the vector field is conservative you have to compute the curl of the vector field and you would get that.

$\mathbf{F}(x,y,z) = (-5x,-4y,1)$

$\nabla \times \mathbf{F} = (0,0,0)$

Therefore your vector field is conservative.

6 0

3 years ago

Benito and Tyler are painting opposite sides of the same fence. Tyler has already painted 19 1/2 feet of his side of the fence w

natali 33 [55]

Answer:

Step-by-step explanation:
Let x be the number of minutes after which both sides have equal number of feet painted,
∵ One side of the fence is painted by Benito,
His speed = 15 ft/min
So, the number of feet painted in one side after x minutes = 15x,
Now, second side of the fence is painted by Taylor,
The feet he already painted = ,
Taylor's speed = 11 ft/min
Thus, the number of feet painted in second side after x minutes = ,

Hence, it will take minutes for both sides to have an equal number of feet painted.

5 0

3 years ago

Read 2 more answers

PLEASE HELP

kaheart [24]

Answer:

use pressure =Force /area

Step-by-step explanation:

12000N/1.08

7 0

3 years ago

A plant produces 500 units/hour of an item with dimensions of 4” x 6” x 2”. The manager wants to store two weeks of supply in co

mart [117]

Answer:

564 ft²

Step-by-step explanation:

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

(4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

47 × 12 ft² = 564 ft²

of warehouse floor space required for storage.

_____

The second attachment shows the top view and side view of units packed in a storage box.

4 0

3 years ago