A solid object where the radius of bse is 7cm and height is 12cm
2 answers:
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Answer:
a) x > − 24
b) x < − 3
c) q < 56
Step-by-step explanation:
a) −2/5x−9<9/10
<=> 2/5x + 9 > − 9/10
<=> 2/5x > − 9/10 − 9
<=> 2×2/2×5x > − 9/10 − 9×10/10
<=> 4/10x > − 99/10
<=> x > − 99/4
<=> x > − 24
b) 4x+6<−6
<=> 4x < − 6 − 6
<=> 4x < − 12
<=> x < − 12/4
<=> x < − 3
c) q+12−2(q−22)>0
<=> q+12−2q −2×(−22)>0
<=> (q−2q) + (12+ 44) >0
<=> −q + 56 >0
<=> q < 56
Answer:
y=-2x-3
Step-by-step explanation:
Since our equation is in standard form Ax+By=C we must first manipulate the equation so that we have it in the slope-intercept form such that y=mx+b. Therefore:
Therefore, our slope is 1/2 and our y-intercept is 2. Now in order to determine a perpendicular line to the one stated above we must then get the negative inverse of our slope meaning (negative reciprocal). Now we must use the point slope formula:
Where m is the slope, x1 is -2 and y1 is 1 (because of the ordered pair given). And so:
Therefore, the line that is perpendicular to -x+2y=4 is y=-2x-3.