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scoundrel [369]
3 years ago
11

The quotient if a number and 9 times it’s reciprocal is 1. Find the number. (Might be more than one answer)

Mathematics
2 answers:
astra-53 [7]3 years ago
5 0
You need to add 9 and 1 which gives you 10
icang [17]3 years ago
5 0

Answer:

You must add the quotient to the reciprocal, which gives you 10.

since 9 + 1 = 10

Step-by-step explanation:

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Can someone help me with Question 22.
adell [148]

Answer:

yes i could help you


Step-by-step explanation:


8 0
3 years ago
Hi everyone! I have a question!
Tju [1.3M]

Answer:

7π

Step-by-step explanation:

SO first find the area of the whole circle

which has a radius of 3

a=πr^2

So 3^2=9

9π

Now the two circles which are the same in area due to having the same radius

so if you plug in the 1 for radius the answer would just be π or 1π

now multiply that by 2 becuase there are 2 identical circles

π*2=2π

Now subtract

9π-2π=7π

3 0
3 years ago
Read 2 more answers
A cryptographic hash takes a message as input and produces a fixed-length string as output, called the digital fingerprint. A br
Allushta [10]

Answer:

1.85x10^{19} attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

3.40*10^{38} attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

Step-by-step explanation:

Each bit has two options. So

How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?

So for each of the 64 bits, we have the following number of options.

2 - 2 - 2 - 2 -... - 2

So, in all, there are

T = 2^{64} = 1.85x10^{19}

options.

So, 1.85x10^{19} attempts are required to find a matching pair if the digital fingerprint is 64 bits long.

128 bits long?

Using the same logic as the first question.

T = 2^{128} = 3.40*10^{38}

So, 3.40*10^{38} attempts are required to find a matching pair if the digital fingerprint is 128 bits long.

5 0
3 years ago
Can you please explain this?​
Leni [432]

Answer:

The question is giving you pairs of points in space which can be used to define lines. It is then asking you to determine if the lines defined by those points are parallel, perpendicular, or neither.

Step-by-step explanation:

Two key things you need to know to solve this is that the lines will be parallel if their slopes are the same, and perpendicular if one slope is the negative reciprocal of the other (i.e. s_{1} = -s_{2}^{-1})

Let's start with question 11. You are given two pairs of points, each of which describes a distinct line:

(3,5)-(1,1) and (0, 2)-(5, 12)

To find the slope of each pair, take the vertex with the lesser x co-ordinate, and subtract it from the vertex with the greater x co-ordinate.  That will give us a valid Δx and Δy to get the slope.

In the first pair, 3 > 1, so we'll subtract the second point from the first:

s = \Delta y / \Delta x\\s = \frac{5 - 1}{3 - 1}\\s = 4/2\\s = 2

So the first pair of vectors describe a line with a slope of 2.  Let's look at the other pair:

s = \Delta y / \Delta x\\s = (12 - 2) / (5 - 0)\\s = 10 / 5\\s = 2

That also gives us a slope of 2, meaning that the two lines are parallel.

This same process will need to be done for the other three questions.  We can't answer questions 12 or 14 here, as the last point is cut off on the edge of the image.  For question 3 though, one line has a slope of 7/3, and the other 3/7. That puts them in the "neither" category, as one is not the negative reciprocal of the other, but instead the positive reciprocal.

6 0
3 years ago
Help with 2&3?? Please will mark brainiest of correct
Murrr4er [49]
2 wrong 3 right because you might added wrong
5 0
3 years ago
Read 2 more answers
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