Becky is collecting money for an fundraiser she wants to collect more than $1,910.00 and has already $281.00. Becky averages $24
2 answers:
Becky needs at least 68 people to donate money into her fundraiser.
The question requests that we write an inequality to show the number of additional people Becky needs to collect from to meet her goal.
Data given;
- Target = $1,910.0
- Per head = $24.00
- Amount collected = $281.00
This is the process of comparing two values to show than either one is greater than or less than the other value.
The inequality of the situation would be
The inequality above would enable us solve for this problem.
From the calculation above, it shows that she needs at least 68 people to donate in order to meet her target.
Learn more on inequalities here;
You might be interested in
Answer:
a) P(x=108)=0.0020
b) P(x≥108)=0.9980
c) P(x<124)=0.7794
d) P(124≤x≤128)=0.1925
Step-by-step explanation:
We know the population proportion, that is p=0.84.
We take a sample of size n=143.
We will use the normal approximation to the binomial distribution to model this problem.
The mean and standard deviation of the normal approximation to the binomial distribution will be:
a) We have to calculate the probability that exactly 108 flights are on time.
As the normal distribution considers the random variable to be continous, we have to apply the continuity correction factor.
In this case, the probability of 108 flights on time can be calculated as P(107.5<x<108.5):
b) Now we have to calculate that at least 108 flights are on time.
As the probability includes 108, the continuity factor will indicates that we calculate P(x>107.5). The z-value for x=107.5 has been already calculated in point a:
c) We have to calculate the probability that fewer than 124 flights are on time. According to the continuity factor, we have to calculate the probability P(x<123.5), as the flight number 124 is not included in the interval.
d) We have to calculate the probability that between 124 and 128 flights, inclusive, are on time.
This interval corresponds to the probability P(123.5<x<128.5)