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DiKsa [7]
2 years ago
12

Solve the graph fjsdjshfdkjfd

Mathematics
1 answer:
Nostrana [21]2 years ago
4 0

Answer:

y=-2x+3

Step-by-step explanation:

Comment if you need steps.

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PLEASE HELP!!
Bezzdna [24]

Answer:

y=-\dfrac{9}{40}x^2+\dfrac{441}{40}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

y=ax^2+b

This parabola passes through the point R(3,9), then

9=a\cdot 3^2+b\\ \\9=9a+b

The area of the right triangle PQR is

A_{PQR}=\dfrac{1}{2}\cdot PQ\cdot QR

Find PQ and QR, if P(x_1,0),\ Q(3,0),\ R(3,9):

PQ=\sqrt{(x_1-3)^2+(0-0)^2}=|x_1-3|\\\\QR=\sqrt{(3-3)^2+(0-9)^2}=9

Now,

40.5=\dfrac{1}{2}\cdot |x_1-3|\cdot 9\\ \\90=9|x_1-3|\\ \\|x_1-3|=10\\ \\x_1-3=10\ \text{or}\ x_1-3=-10\\ \\x_1=13\ \text{or }x_1=-7

We get two possible points P_1(-7,0) and P_2(13,0).

For point P_1:\\

0=a\cdot (-7)^2+b\\ \\49a+b=0

So,

b=-49a\\ \\9=9a-49a\\ \\-40a=9\\ \\a=-\dfrac{9}{40}\\ \\b=\dfrac{441}{40}\\ \\y=-\dfrac{9}{40}x^2+\dfrac{441}{40}

For point P_2:\\

0=a\cdot (13)^2+b\\ \\169a+b=0

So,

b=-169a\\ \\9=9a-169a\\ \\-160a=9\\ \\a=-\dfrac{9}{160}\\ \\b=\dfrac{1,521}{160}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}

5 0
3 years ago
PLEASE HELPPPPPP
N76 [4]

Answer:

D

Step-by-step explanation:

in the question the scale factor is 4 so that means it is a dilation (getting larger) because the scale factor is >1

7 0
2 years ago
Read 2 more answers
Out of 284 high school students surveyed, how many favored football?
Lynna [10]
Is there a picture to go with it?
5 0
3 years ago
What’s the answer please i don’t need work shown :)
Lady bird [3.3K]

Answer:

102

You didn't ask for work and I shall respect your wish

6 0
3 years ago
9³•9⁴ [?]<br>-------- • 9³ = 9<br> 9²​
Colt1911 [192]

9514 1404 393

Answer:

  9⁸

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

  \dfrac{9^3\cdot9^4}{9^2}\cdot9^3=9^{3+4-2+3}=\boxed{9^8}

7 0
3 years ago
Read 2 more answers
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