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3 years ago

Red balloons float orange marbles at a ratio of 6:4.

Mathematics

1 answer:

Artyom0805 [142]3 years ago

3 0

Answer:

16 marbles.
15 balloons.

Step-by-step explanation:

Question-1 solution:

We can solve this question with the help of proportion. Seek solution below!

6:4 = 24:x
=> 6x = 96
=> x = 16

Hence, for question 1, the answer is 16 marbles.

Question-2 solution:

We can solve this question with the help of proportion. Seek solution below!

6:4 = x:10
=> 60 = 4x
=> x = 15

Hence, for question 2, the answer is 15 balloons.

Hoped this helped.

$BrainiacUser1357$

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A man gained rs. 3000 by selling a mobile set allowing 15 % discount on the marked price the loss would be rs. 8000. Find the ma

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Answer:

Marked price is Rs. 53333.33 and the cost price is Rs. 42333.33.

Step-by-step explanation:

Let Rs. x and Rs. y are the cost price and marked price of the mobile set respectively.

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4 years ago

If the rat moves through the maze randomly, out of 100 attempts, how many times would you expect Romeo to end up in room A? How

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50 and 50 because half of 100 is 50 and 50

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3 years ago

The row-echelon form of the augmented matrix of a system of equations is given. Find the solution of the system.

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Answer:

option-C

Step-by-step explanation:

We are given row-echelon form

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Let's assume

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now, we can find x and y

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3 years ago

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The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =

Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

dL(t)/dt = 34.416*e^(-0.18*t)

- Then use the above relation to compute:

L'(t) = 34.416*e^(-0.18*t)

L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

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6 cm/yr = 34.416*e^(-0.18*t)

e^(0.18*t) = 34.416 / 6

0.18*t = Ln(34.416/6)

t = Ln(34.416/6) / 0.18

t = 10 year

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