Tyler orders a meal that costs $15.

Mathematics

1 answer:

olganol [36]2 years ago

6 0

The answer is 69 dollars and the titian would be 69 dollas

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-x - 1 = 221 + 2x <br> plzzzzzzzzz help

Otrada [13]

$Simplifying
-1x + -1 = 221 + 2x

Reorder the terms:
-1 + -1x = 221 + 2x

Solving
-1 + -1x = 221 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-1 + -1x + -2x = 221 + 2x + -2x

Combine like terms: -1x + -2x = -3x
-1 + -3x = 221 + 2x + -2x$
$Combine like terms: 2x + -2x = 0
-1 + -3x = 221 + 0
-1 + -3x = 221

Add '1' to each side of the equation.
-1 + 1 + -3x = 221 + 1

Combine like terms: -1 + 1 = 0
0 + -3x = 221 + 1
-3x = 221 + 1

Combine like terms: 221 + 1 = 222
-3x = 222

Divide each side by '-3'.
x = -74

Simplifying
x = -74$

5 0

3 years ago

For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!

Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

$x^2-2x-(c+4)=0$ .

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic $ax^2+bx+d$ , the discriminant is $\sqrt{b^2-4ad}$ .

(The discriminant is more commonly known as $\sqrt{b^2-4ac}$ , but I changed the variable since we already have a $c$ in the quadratic given.)

In the quadratic above, we have $a=1$ , $b=-2$ , and $d=-(c+4)$ . Plugging this into the formula for the discriminant, we have

$\sqrt{(-2)^2-4(1)(-(c+4))$ .

Using the distributive property to expand and simplifying, the expression becomes

$\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.$