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GrogVix [38]
3 years ago
8

What is the answer to this table?

Mathematics
2 answers:
rjkz [21]3 years ago
7 0

Answer:     -3

Step-by-step explanation:

stiv31 [10]3 years ago
6 0
-3
You would do (x1-y1 over x2-y2) !!
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Alexxandr [17]

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3 years ago
Find the vertex form for the following quadratic function. f(x)=x^2+14x+41
Luda [366]

f(x) = (x + 7)² - 8

the equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

given the quadratic in standard form : y = ax² + bx + c ( a ≠ 0 )

then the x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = x² + 14x + 41 is in standard form

with a = 1, b = 14 and c = 41

x_{vertex} = - \frac{14}{2} = - 7

substitute this value into the equation for y- coordinate

y = (- 7 )² + 14(- 7 ) + 41 = 49 - 98 + 41 = - 8

f(x) = (x + 7)² - 8 ← in vertex form


7 0
4 years ago
If ZDCE is an obtuse angle. CF bisects ZDCE.MZDCF = 2? + 4 and m DCE = 3z? – 7x, what is the value of x?
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Answer:

x=2.345208,−2.345208

Step-by-step explanation:

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