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GrogVix [38]
3 years ago
8

What is the answer to this table?

Mathematics
2 answers:
rjkz [21]3 years ago
7 0

Answer:     -3

Step-by-step explanation:

stiv31 [10]3 years ago
6 0
-3
You would do (x1-y1 over x2-y2) !!
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Point-Slope:

y+16=-1/26*(x-19)

Finding the regular slope:

m=1/-26=0.03846

7 0
3 years ago
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Practice: triangle sum theorem on a piece of paper solve for the variable , then find the missing angles
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3 years ago
It was reported that 23% of U.S. adult cellphone owners called a friend for advice about a purchase while in a store. If a sampl
leva [86]

Answer:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.23)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want to find the following probability:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

5 0
3 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
What are the coordinates to y equals -2​
Sliva [168]

Answer:

boi

Step-by-step explanation:

5 0
4 years ago
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