First, that looks like Pearson and if it is, I'm so sorry for you.
Secondly, I think this answer is correct.
Answer:
1 Expert Answer
Let x and y be the two numbers. Then by assumptions we have x+y=30 and x-y=20. Hence, y=x-20 and by plugging this into the first equation we obtain x+x-20=30 or 2x=50 or x=25 and y=5
Step-by-step explanation:
So, divide 30 by 2 . That gives you 15 for x, 15 for y. Now, you have difference of six, divide by two, that equals 3.
Answer:
a=4
c=5
e=7
f=1
Step-by-step explanation:
the simplest method would be to start with a(2)"squared" (being '4' as this will get you closest to 15. So 16 -1 (being 'c') = 15. now plug those into the other equations and work the other numbers out.
