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2 years ago

If there are four slices of turkey on Hector's sandwich, how much does the turkey on his sandwich cost?

Mathematics

1 answer:

pishuonlain [190]2 years ago

7 0

Answer:

3.22580645161

Step-by-step explanation:

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A garden is designed in the shape of a rhombus formed

Usimov [2.4K]

Answer:

120ft.

Step-by-step explanation:

A garden is designed in the shape of a rhombus formed from 4 identical 30°-60°-90° triangles. The shorter distance across the middle of the garden measures 30 feet. What is the distance around the perimeter of the garden? 120ft.

4 0

2 years ago

If you just write whatever just for the points i will report you.

Hoochie [10]

Answer:

Below!

Step-by-step explanation:

The best way to answer this question is to read the statement carefully.

=> Five less than twice a number = 2x - 5
=> Five times the sum of two numbers = 5(x + y)
=> The difference of 5 and a number, squared = (5 - x)²

Hoped this helped.

$BrainiacUser1357$

5 0

2 years ago

Read 2 more answers

Help

kykrilka [37]

Let n = the hours elapsed when the two trains are 660 miles apart.

Let the first train travel east and the second train travel west.

The distance traveled by the first train is

x = (50 mi/h)*(n h) = 50n mi

The distance traveled by the second train is

y = (60 mi/h)*(n h) = 60n h

The distance between the two trains after n hours is

x + y = 50 n + 60n = 110n mi

Because this distance is 660 miles, therefore

110n = 660

n = 6 hours

Answer: 6 hours

I hope this helps. Sorry it took so long

3 0

3 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$