Mr. Howell spends his day as follows: sleep-

Mathematics

1 answer:

Naily [24]3 years ago

6 0

Sleeping: 31%
Working: 38%
Eating: 8%
Chores: 11%
Leisure: 8%
Bible Devotions: 4%

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What is the slope and y-intercept of y=4x+2

kaheart [24]

Answer:

slope: 4

y-intercept: 2

Step-by-step explanation:

We are given an equation, y = 4x + 2, and we are asked to find the slope and y-intercept of the line. Looking carefully, we can see that the equation is given to us in slope-intercept form.

Slope-intercept form is:

y = mx + b

where m is the slope and b is the by-intercept.

Knowing this, we can find that 4 is the slope of the line and 2 is the y-intercept.

I hope you find my answer and explanation to be helpful. Happy studying.

4 0

3 years ago

Can the quadratic polynomial x2+kx+k have equal zeroes for some odd integer k>1

PilotLPTM [1.2K]

No.
The only value that can be put in K that would have the same zeros would be 4 but 4 is not an odd integer. If there was an odd integer that the sum and product would be the same then it would lie on the x-axis. but only 4 fits the criteria.

7 0

3 years ago

I need help ASAP

dem82 [27]

Answer:

The inequality is 6 + 3x ≤ 12 or x ≤ 2 .

Step-by-step explanation:

Given that $6 is for admission which is a fixed amount, $3 is charged per hour and must not spend more than $12. So the inequality will be :

Let x be the no. of hours,

6 + 3x ≤ 12

Solve :

6 + 3x ≤ 12

3x ≤ 12 - 6

3x ≤ 6

x ≤ 6 ÷ 3

x ≤ 2

4 0

2 years ago

Read 2 more answers

Please help!!

yarga [219]

Because this is a fourth degree that will be tricky to factor as it is, we will do a u substitution. Let $x^2=u$ . We can now rewrite that polynomial in terms of u: $u^2-7u-8=0$ . Filling into the quadratic formula we have $u=\frac{7+/-\sqrt{49-4(1)(-8)}}{2}$ . Simplifying down $u=\frac{7+/-\sqrt{81}}{2}$ and $u=\frac{7+9}{2}$ or $u=\frac{7-9}{2}$ . That means that u = 8 or u = -1. But don't forget that we let $u=x^2$ , so we have to put x-squared back in for u. That gives us $x^2=8$ which simplifies down to $+/-2\sqrt{2}$ . That also gives us $x^2=-1$ . When we take the square root of -1, we have to use the fact that -1 = i^2, so we sub that in to get $x=+/-i$ . All in all, your solutions are as follows: $2\sqrt{2},-2\sqrt{2},i,-i$ which is choice b.