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crimeas [40]
2 years ago
8

Captain Brewster captured a pack of aliens. The following data points represent the lengths of each of the aliens' big toes (in

centimeters). 18, 16, 17, 17, 16, 15, 16. Using this date, create a dot plot where each dot represents a big toe.
Mathematics
1 answer:
n200080 [17]2 years ago
3 0

Answer:

15 ·

16 ···

17 ··

18 ·

19

Step-by-step explanation:

There were 2 aliens that each have big toes measuring 17 cm long. So, the 17 would have 2 dots above it:

17 ··

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HELP ASAP PLS! The ratio of bows to headbands of Monique’s hair accessories is 8:4. Select all true statements.
Ratling [72]
Obviously a b c & d.
3 0
3 years ago
What is in the middle of 0 and 1
Mashcka [7]

Answer:

.5

Step-by-step explanation:

That 0 between 1 is .5

8 0
4 years ago
Read 2 more answers
-6(2+n) is greater than 72
Hitman42 [59]

Answer:

n > -14

Step-by-step explanation:

Firstly, you use the distributive property;

-12 - 6n > 72

Then, since 12 is negative, you add 12 to both sides;

-12 - 6n > 72

+12           +12

-6n > 84

Then you divide both sides by -6 to get n > -14.


Shoot, hold on; this is an edit; did you mean that 72 is greater than -6(2 + n) or did you accidentally flip the sign in the picture? Hopefully I did what you needed.


5 0
3 years ago
Read 2 more answers
Please someone help me with this word problem for my math class T.T
olga55 [171]

Answer:

<u>Perimeter</u>:

= 58 m (approximate)

= 58.2066 or 58.21 m (exact)

<u>Area:</u>

= 208 m² (approximate)

= 210.0006 or 210 m² (exact)

Step-by-step explanation:

Given the following dimensions of a rectangle:

length (L) = \sqrt{252} meters

width (W) = \sqrt{175} meters

The formula for solving the perimeter of a rectangle is:

P  = 2(L + W) or 2L + 2W

The formula for solving the area of a rectangle is:

A = L × W

<h2>Approximate Forms:</h2>

In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.  

13² = 169

14² = 196

15² = 225

16² = 256

Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width).  We can use these values to approximate the perimeter and the area of the rectangle.

P  = 2(L + W)

P = 2(13 + 16)

P = 58 m (approximate)

A = L × W

A = 13 × 16

A = 208 m² (approximate)

<h2>Exact Forms:</h2>

L = \sqrt{252} meters = 15.8745 meters

W = \sqrt{175} meters = 13.2288 meters

P  = 2(L + W)

P = 2(15.8745 + 13.2288)

P = 2(29.1033)

P = 58.2066 or 58.21 m

A = L × W

A = 15.8745 × 13.2288

A = 210.0006 or 210 m²

8 0
3 years ago
1. what is the period of the function f(x) shown in the graph?
ki77a [65]
Problem 1)

Answer: pi/2

-------------------------------

Place your pencil at (0,3) which is a good starting point, since x = 0 is often a good starting point. Trace along the curve until you reach back up at y = 3 again. So you'll go down and then back up until you reach (pi/2, 3). The difference in x values is pi/2-0 = pi/2. Every pi/2 units, the graph curve repeats itself over and over infinitely. 

Note: this is not the only way to determine the period. You can start at any point really. It helps to start at a min or max value, or at x = 0. In this case, it happened to be both. 

===========================================================
Problem 2)

Answer: See figure 2 (attached image)

-------------------------------

Point A is at (0,0)
Point B is at approximately (1.57,-2) which is exactly (pi/2,-2)

===========================================================
Problem 3)

Answer: See figure 3 (attached image)

===========================================================
Problem 4)

Answer: Choice B
The graph is horizontally compressed by a factor of 2 and shifts up 1 unit

-------------------------------

The jump from x to 2x will have the period go from 2pi to pi. The graph curve repeats itself more and more often (twice as often). Therefore we have an accordion squeeze effect going on, or think of it like a spring being pressed down. We have horizontal compression along the x axis.

Adding 1 to the end shifts every point upward 1 unit. Overall, this gives the visual the entire curve itself is shifted up 1 unit.

===========================================================
Problem 5)

Answer: f(x) = 5.05*sin((pi/12)x)+5.15

-------------------------------

max = 10.2
min = 0.1
difference = 10.2-0.1 = 10.1
Divide this difference in half: 10.1 = 5.05
So a = 5.05 is the amplitude

The period is T = 24 hrs since the height is 5.15 at midnight of one day, it rises and then falls and rises back to 5.15 by the next midnight
b = 2pi/T = 2pi/24 = pi/12
c = 0 since there is no phase shift in this sine function

d = 5.15 is the midline, which is the starting height at x = 0

f(x) = a*sin(bx-c)+d
f(x) = 5.05*sin((pi/12)x-0)+5.15
f(x) = 5.05*sin((pi/12)x)+5.15

===========================================================
Problem 6)

Answers are:
A) The max height of the Ferris wheel is 64 ft
B) The radius of the Ferris wheel is 30 ft

-------------------------------

The largest height of the table is 64, so 64 is the max height. This is why A is true.

B is true since the max is 64 and the min is 4, so 64-4 = 60 is the diameter, making the radius r = d/2 = 60/2 = 30

C is false because the height at t = 0 is 34 ft, but the lowest point is at height h = 4

D is false because the period is actually 10 seconds. Eg: going from t = 7.5 to t = 17.5 is a time of 10 seconds. During this time, the heights are 4, 34, 64, 34, 4 telling us that a full cycle has taken place.

===========================================================

4 0
3 years ago
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