Answer:
(1, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 3
y = -3x + 6
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 3 = -3x + 6
- [Subtraction Property of Equality] Subtract 6 on both sides: -3 = -3x
- [Division Property of Equality] Divide -3 on both sides: 1 = x
- Rewrite/Rearrange: x = 1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3(1) + 6
- Multiply: y = -3 + 6
- Add: y = 3
You answer would be 0.012345678.
Calculate it
Answer:
steps below
Step-by-step explanation:
y = (x-3) / x
replace x and y: x = (y-3) / y
y - 3 = xy
y - xy = 3
y(1 - x) = 3
y (f'(x)) = 3 / (1-x)
Answer:
The half-life of the radioactive substance is 135.9 hours.
Step-by-step explanation:
The rate of decay is proportional to the amount of the substance present at time t
This means that the amount of the substance can be modeled by the following differential equation:

Which has the following solution:

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.
After 6 hours the mass had decreased by 3%.
This means that
. We use this to find r.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is 135.9 hours.
Answer:
19x+8
Step-by-step explanation:
1) distribute the term outside the parenthesis to each term inside:
4*3x=12x
4*2=8
12x+8-7x
2) 12x+7x=19x
19x+8
Hope this helps!