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inysia [295]
3 years ago
5

-5x+y=6 -3x+6y=-12 Solving systems of equations by substitution

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

if you isolate y in the top equation to get y=5x+6 then you can substiture y for 5x+6 in the bottom equation because thats what y equals

as of now you have -3x+6(5x+6)=-12 but if you use the distrubite property you would get -3x+30x+36=-12

then if you subtract 36 from both sides you would get -3x+30x=-48 then combine like terms to get 27x=-48 then divide both sides by 27 to get x=\frac{-48}{27} or x≈1.8

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Solve this system by substitution. y = 3 y = -3x + 6 *Remember to write your answer as a coordinate point (x, y). I​
DochEvi [55]

Answer:

(1, 3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 3

y = -3x + 6

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in <em>y</em>:                                                                                                 3 = -3x + 6
  2. [Subtraction Property of Equality] Subtract 6 on both sides:                      -3 = -3x
  3. [Division Property of Equality] Divide -3 on both sides:                                1 = x
  4. Rewrite/Rearrange:                                                                                        x = 1

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                               y = -3(1) + 6
  2. Multiply:                                                                                                           y = -3 + 6
  3. Add:                                                                                                                 y = 3
6 0
2 years ago
Write 12345678 times 10^-9 as a decimal.
labwork [276]
You answer would be 0.012345678.
 Calculate it 
5 0
3 years ago
Read 2 more answers
Please help!! second time posting !! algebra question, about functions!
kodGreya [7K]

Answer:

steps below

Step-by-step explanation:

y = (x-3) / x

replace x and y:    x = (y-3) / y

y - 3 = xy

y - xy = 3

y(1 - x) = 3

y (f'(x)) = 3 / (1-x)

6 0
3 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
2 years ago
4(3x+2)−7x simplified
baherus [9]

Answer:

19x+8

Step-by-step explanation:

1) distribute the term outside the parenthesis to each term inside:

4*3x=12x

4*2=8

12x+8-7x

2) 12x+7x=19x

19x+8

Hope this helps!

7 0
3 years ago
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