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Y=kx+b
line is perpendicular y=1/3x+6⇒ k=-
=-3
so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15
P.s.picture<span> to test solutions <span>in the application</span></span>
line is perpendicular y=1/3x+6⇒ k=-
so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15
P.s.picture<span> to test solutions <span>in the application</span></span>
<u>Answer:</u>
The equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 is
<u>Solution:</u>
Given that line passes through (-2, -6) and has slope of 1/3
We have to find the equation of the line
The point slope form is given as
where m is the slope of the line and a, b are the x, y coordinates of the given point through which the line passes.
Here in this question, m = 1/3 and a = -2 and b = -6
By substituting in point slope form we get,
Hence the equation of a line, in point slope form that passes through (-2, -6) and has a slope of 1/3 is