What is the distance between the points (10, 3) and (-2, -2) in the coordinate plane?
1 answer:
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Answer:
Option (2). 1
Step-by-step explanation:
Coordinates of point A, B, C and D are,
A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).
Quadrilateral ABCD when rotated 90° clockwise about the origin,
Rule for the rotation of the vertices,
(x, y) → (y, -x)
Following the rule of rotation coordinates of the image points,
A(-4, 4) → A'(4, 4)
B(-2, 4) → B'(4, 2)
C(-2, 1) → C'(1, 2)
D(-4, 3) → D'(3, 4)
Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.
Option (2) is the correct option.
Given that a triangle in the coordinate plane has coordinates of (3, 5), (1, −3), and (−3, 4). Now these points are translated and the new coordinates are (1, 7), (−1, −1), and (−5, 6).
Questioon says to find which type of translation occured from the given choices.
It can be easily found by drawing the given coordinates.
Original position of the triangle is drawn in Brwon colour.
New position of the triangle is drawn in Green colour.
From graph we can clearly see that each of the original coordinate moves two unit left then 2 units upward to get new coordinate.
Hence choice "A) It moved left two units and up two units." is the final answer.
