Which of the following functions has a period of 8 π ?
1 answer:
<h3>Answer: Choice B</h3>
Explanation:
The general template of a sine function is
y = Asin(B(x-C))+D
The value of B is the only thing that determines the period T. We ignore every other term.
It turns out that T = 2pi/B which can be solved to B = 2pi/T
Plug in the given period of T = 8pi and compute to get
B = 2pi/T
B = (2pi)/(8pi)
B = 2/8
B = 1/4
This means that the term out front of the x is 1/4 and the equation must be which matches with answer choice B.
You might be interested in
<em>Note:</em>
<em>Your first question is missing the y-intercept, so I am solving the 2nd question. You would still get your concept clear because the procedure to solve each of the questions is the same.</em>
Question 2
Answer:
The equation in the standard form is:
- 2/3x + y = -4
Please also check the attached graph.
Step-by-step explanation:
We know that the equation in the standard form is
Ax + By = C
where x and y are variables and A, B and C are constants
Given
- Slope m = -2/3
- y-intercept = -4
To determine
- Write the equation in the standard form
We know that the slope-intercept form of the line equation
where
- m is the slope
- b is the y-intercept
In our case:
- Slope m = -2/3
- y-intercept = -4
substituting m = -2/3 and y-intercept b = -4 in the slope-intercept of the line equation
y = mx+b
y = -2/3x + (-4)
y = -2/3x - 4
Writing the equation in the standard form
2/3x + y = -4
Therefore, the equation in the standard form is:
- 2/3x + y = -4
Please also check the attached graph.
