Which of the following functions has a period of 8 π ?
1 answer:
<h3>Answer: Choice B</h3>
Explanation:
The general template of a sine function is
y = Asin(B(x-C))+D
The value of B is the only thing that determines the period T. We ignore every other term.
It turns out that T = 2pi/B which can be solved to B = 2pi/T
Plug in the given period of T = 8pi and compute to get
B = 2pi/T
B = (2pi)/(8pi)
B = 2/8
B = 1/4
This means that the term out front of the x is 1/4 and the equation must be which matches with answer choice B.
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So hmm the food C = 6p + 3q and the food D = 4.5p + 1.5q
now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component
so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3
and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20
now the "p" part... ends up as
that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M
now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component
so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3
and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20
now the "p" part... ends up as
that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M