Which of the following functions has a period of 8 π ?
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
<h3>
Answer: Choice B</h3>
Explanation:
The general template of a sine function is
y = Asin(B(x-C))+D
The value of B is the only thing that determines the period T. We ignore every other term.
It turns out that T = 2pi/B which can be solved to B = 2pi/T
Plug in the given period of T = 8pi and compute to get
B = 2pi/T
B = (2pi)/(8pi)
B = 2/8
B = 1/4
This means that the term out front of the x is 1/4 and the equation must be  which matches with answer choice B.
 which matches with answer choice B.
 
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