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romanna [79]
3 years ago
6

Sarah wants to find out how much time it would take to drive from her home to New York. At an average, she would drive at 55 mil

es per hour. If the distance to be covered is 1150 km and a mile equals 1. 61 km, how much time will the trip take (to the nearest hour)? 13 hours 21 hours 29 hours 34 hours.
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

A

Step-by-step explanation:

d = 1150 km = 1150 km / 1.61 miles = 714.29 miles

r = 55 mph

d / r = time

714.29 / 55 = 12.99 hours.

The closest time to that is 13 hours.

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A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid
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Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 865, \pi = \frac{408}{865} = 0.4717

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

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