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3 years ago

13

Bradley's sleeping bag weighs 7 pounds.

2 answers:

satela [25.4K]3 years ago

6 0

28 pounds
35 (together) - 7 (sleeping bag)

Y_Kistochka [10]3 years ago

3 0

The backpack weighs 28 pounds without the sleeping bag.

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Solve the inequality.

borishaifa [10]

2>8-4h/3 subtract 8 from both sides

-6>-4h/3 multiply both sides by 3

-18>-4h divide both sides by -4 (and reverse sign because of division by a negative value)

4.5<h or by convention...

h>4.5

8 0

3 years ago

In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

2 years ago

What is the area of the triangle?

Roman55 [17]

Answer:

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Step-by-step explanation:

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2 years ago

X−6>−2 solve the inequality

hjlf

Answer:

x>4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Do you have a balance of -4 dollars in a savings account after making a deposit yet $25 in his account what is the overall chang

Natali5045456 [20]

The answer would be 21

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3 years ago