Please help me! <br><br><br>ty :)

Determine the equation of a horizontal line that passes through (4,7)

professor190 [17]

Y=7 because there is no slope and the Y intercept is at 7.

5 0

3 years ago

Cómo se escribe el número 90 en egipcio

dmitriy555 [2]

If you're talking about Egyptian, you have to put 9 "ten" symbols on the paper and you get 90.
The "ten" symbol looks like a tiny arch.

7 0

3 years ago

Help!!! Assignment due in 20 minutes!!

Vitek1552 [10]

Answer:

2

Step-by-step explanation:

The answer would be 2 because it reduces to the same system of equations as the original, which I knew since the first equation was the same and if you divide everything in the second by 2, you'll get 3x-y=8. :)

7 0

3 years ago

Given: TSR and QRS are right angles; T ≅ Q

allsm [11]

Answer:

The answer is number (2) ⇒ because of the AAS congruence theorem

Step-by-step explanation:

* Lets use the information to solve the problem

- In the given triangles TSR and QRS

# We have a common side RS or SR

# Two right angles TSR and QRS

# m∠T = m∠Q ⇒ given

* So we have two pairs of angles and one common side, lets

revise the cases of congruence

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

* Now lets read the statements and write the missing

Step 1: m∠TSR = m∠QRS = 90° ⇒ because all right angles are congruent

Step 2: m∠T = m∠Q ⇒ because it is given

Step 3: SR ≅ RS ⇒ because of reflexive property (common side)

Step 4: Δ TSR ≅ ΔQRS ⇒ because of the AAS congruence theorem

* The answer is number (2)

4 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

2 years ago

Please help me! ty :)