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vampirchik [111]
3 years ago
6

Let f(x)=5x+5 find f(-1)I need your help with this. please help me​

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0

f(x) = 5x+5\\\\f(-1) = 5(-1) +5  = -5+5=0

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DE=2x <br> EF=2x-6<br> DF=3x+5<br> What is DE
Nataly_w [17]

Answer:

DE=2x you kinda put the answer

Step-by-step explanation:

5 0
3 years ago
Help me please nobody seems to help me :(
podryga [215]

Answer:

A: (4, -2)

B: (-3, -3)

C: (-2, 5)

D: (-3, -3)

E: (1, -4)

F: (0, 3)

6. Option B

Step-by-step explanation:

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3 years ago
Which points are on the graph of f(x) = RootIndex 3 StartRoot x EndRoot? Check all that apply. (–27, –3) (–1, 1) (0, 0) (1, 1) (
Vanyuwa [196]

Answer:

(-27,-3) (0,0) (1,1)

Step-by-step explanation:

Because I got it right xD

6 0
3 years ago
Read 2 more answers
1<br>Determine the value of k if g(x)=4x+k is a tangent to f(x)=-x²+8x+20​
tangare [24]

Answer:

k=24

Step-by-step explanation:

The tangent of the function f at x=a, can be found by differentiating f w.r.t. x and then replacing x with a.

f=-x^2+8x+20

Differentiating both sides:

f'=(-x^2+8x+20)'

By sum rule:

f'=(-x^2)'+(8x)'+(20)'

By constant multiple rule:

f'=-(x^2)'+8(x)'+(20)'

By constant rule:

f'=-(x^2)+8(x)'+0

By power rule:

f'=-2x+8

f' at x=a is -2a+8

This is the slope of any tangent line to the curve f.

The slope of g is 4 if you compare it to slope intercept form y=mx+b.

So we gave -2a+8=4.

Subtracr 8 on both sides: -2a=-4

Divide both sides by -2: a=2

The tangent line to the curve at x=2 is y=4x+k.

To tind y we must first know the y-coordinate of the point of tangency.

If x=2, then

f(2)=-(2)^2+8(2)+20=-4+16+20=12+20=32

So the point is (2,32).

g(x)=4x+k and we know g(2)=32.

This gives us:

32=4(2)+k

32=8+k

k=32-8

k=24

6 0
2 years ago
Please help me out!!
d1i1m1o1n [39]
Can do.

Arc length = radius * theta.
S=r*theta

Convert 73° to radians.
(73°)*(pi/180)
73°=1.274rad


S=(6.48in.)(1.274rad) = 8.255 in = final answer
8 0
3 years ago
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