Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Answer:
x= 8
Step-by-step explanation:
60/48=1.25
15/1.25= 12
12-4=8
Answer: 5894.2
Step-by-step explanation:
You'll want to follow PEMDAS to simplify this expression.
1.) P - Parentheses
2.) E - Exponents
3.) M - Multiplication
4.) D - Division
5.) A - Addition
6.) S - Subtraction
We'll start with what's inside the parentheses:
(2.4 × 1018) + (3.4 × 1015)
(2,443.2) + (3,451)
Now all you have to do is add the values together to get your answer!
2,443.2 + 3,451
5894.2
Answer:
22.77°
Step-by-step explanation:
Using SOH CAH TOA trigonometry identity
Height of the building (opposite side) = 172ft
Length of the shadow (hypotenuse) = 444ft
Using SOH
sin theta = opp/hyp
Sin theta = 172/444
Sin theta = 0.387
theta = arcsin0.387
theta = 22.77°
Hence the angle of depression is 22.77°
A like term is when the variable, in this case xy, is the same in another term.
So the like term of -18xy is B. 4xy
