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1 year ago

How do you save a document in a format so that any reader can view it?

Computers and Technology

1 answer:

dedylja [7]1 year ago

6 0

You save and download it and then convert it into a format by eight clicking and open as

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Life Decisions Cyber Cafe is a cafe with free Internet service and computers that are linked to various online career opportunit

djverab [1.8K]

Answer:

The correct answer is d) all of the above

Explanation:

The size of the info is necessary to give the users heads up about the amount of data needed to access it, the type of the video is also important so the user can know the environment appropriate for viewing it and also tips for viewing will help users know the requirements needed to view it.

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2 years ago

PLEASE HELP ANSWER THIS only if you know BOTH ANSWERS!

Leya [2.2K]

Answer:

For the first question I think it is chains

The second question.

The woman is suspicious at hotel doors have numbers so how could he have been confused

Explanation:

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3 years ago

Read 2 more answers

Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing

Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

$t=\frac{1 }{(S + (1- S)/N) }$

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

$t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671$

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

$t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181$

Speedup gain is 1.81 times.

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3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

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2 years ago

When the narrator of "EPIC 2015" describes the year 2015 as the "worst of

denpristay [2]

Answer:

A. computers will be replaced by new technology

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2 years ago