Answer:
180
Step-by-step explanation:
Answer: A 2.7 x 10^9
Explanation: brain go brrrrr
Answer:
You do it like this (5times9)=1-(3times3)=41
Step-by-step explanation:
Answer:

Step-by-step explanation:
This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

Integration on both sides gives

where
is a constant of integration.
The steps for solving the integral on the right hand side are presented below.

Therefore,

Multiply both sides by 

By taking exponents, we obtain

Isolate
.

Since
when
, we obtain an initial condition
.
We can use it to find the numeric value of the constant
.
Substituting
for
and
in the equation gives

Therefore, the solution of the given differential equation is

The correct answer is option B.
From the graph we can see the following discontinuities:
a) A hole at x = -2
b) A jump at x = 0
c) A hole at x = 8
The hole refers to the point discontinuity and the jump refers to as jump discontinuity. The function is defined and is continuous at x = 3
Thus, the given graph has jump discontinuity at x = 0 and point discontinuity at x = -2 and x = 8