Answer:
96
Step-by-step explanation:
Here again are the multiples of 6, 0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96,… If we divide any of these multiples by 6, we get a quotient with remainder zero.
f(x)=2x^3+2x^2-4x
The zeros of polynomial functions
2x^3 + 2x^2 - 4x = 0
2x(x^2 + x - 2) = 0
2x(x - 1)(x + 2) = 0
2x = 0; x = 0
x - 1 = 0; x = 1
x + 2 = 0; x = -2
Answer
x = -2 , 0 , 1
Hello I did a call in a couple hours I did call 83
Basically it's telling you what equation to use for the specific value of g(x). If x is g(2) then you would use the third equation. 2x - 5. so 2(2)-5= -1
