Character Map ... I hope This Helps
Answer:
<em>Given Data:</em>
<em>myBytes BYTE 10h, 20h, 30h, 40h </em>
<em>myWords WORD 3 DUP(?), 2000h </em>
<em>myString BYTE "ABCDE"</em>
<em />
Based on the data that we are given we can conclude that:
(a). a. EAX = 1
b. EAX = 4
c. EAX = 4
d. EAX = 2
e. EAX = 4
f. EAX = 8
g. EAX = 5
Answer:
Explanation:
Following are the Semaphores:
Customers: Counts waiting customers;
Barbers: Number of idle barbers (0 or 1)
mutex: Used for mutual exclusion.
Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves
Shared data variable:
count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.
// shared data
semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;
int count_cust= 0;
void barber() {
while(true) { //shop is always open
wait(customers); //sleep when there are no waiting customers
wait(mutex); //mutex for accessing customers1
count_cust= count_cust-1; //customer left
signal(barbers);
signal(mutex);
cut_hair();
}
}
void customer() {
wait(mutex); //mutex for accessing count_cust
if (count_cust< n) {
count_cust= count_cust+1; //new customer
signal(customers); signal(mutex);
wait(barbers); //wait for available barbers get_haircut();
}
else { //do nothing (leave) when all chairs are used. signal(mutex);
}
}
cut_hair(){ waiting(cutting);
}
get_haircut(){
get hair cut for some time; signal(cutting);
}
Answer:
The best answer is "D"
server needs ddr4 memory and ddr3 is installed.
Explanation:
Installing ddr4 memory and ddr3 on the server will not allow the server to recognize all of the memory installed at the same time. This will help the technician for the installation one at a time.
I believe the answer could be the first choice. I'm not quite sure, though
