Which site had a major influence on the social gaming site Friendster?

Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th

ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0

3 years ago

Say you're designing your own operating system, and you want to implement your own paging system. Give one advantage of having s

zheka24 [161]

Answer and Explanation:

Advantages of having large page sizes: Smaller page table, less page faults, less overhead in reading/writing of pages.

Advantages of having small page sizes: reduces internal fragmentation, better with locality of reference.

7 0

4 years ago

Read 2 more answers

Define a function UpdateTimeWindow() with parameters timeStart, timeEnd, and offsetAmount. Each parameter is of type int. The fu

NARA [144]

Answer:

Here is a UpdateTimeWindow() method with parameters timeStart, timeEnd, and offsetAmount

// the timeEnd and timeStart variables are passed by pointer

void UpdateTimeWindow(int* timeStart, int* timeEnd, int offsetAmount){

// this can also be written as *timeStart = *timeStart + offsetAmount;

*timeStart += offsetAmount; //adds value of offsetAmount to that of //timeStart

// this can also be written as *timeEnd = *timeEnd + offsetAmount;

*timeEnd += offsetAmount; } //adds value of offsetAmount to that of //timeEnd

Explanation:

The function has three int parameters timeStart, timeEnd, and offsetAmount.

First two parameters timeStart and End are passed by pointer. You can see the asterisk sign with them. Then in the body of the function there are two statements *timeStart += offsetAmount; and *End+= offsetAmount; in these statements the offsetAmount is added to the each of the two parameters timeStart and timeEnd.