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Lelu [443]
3 years ago
7

You are certain to get 3 jacks when selecting 51 cards from a shuffled deck. Express the indicated degree of likelihood as a pro

bability value between 0 and 1 inclusive.
Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

0.001145

Step-by-step explanation:

Given that you are certain to get 3 jacks when selecting 51 cards from a shuffled deck.

When we draw 3 cards from 51 cards, we keep one card aside

The card can be either Jack or non Jack

Prob (the left over card to be Jack) = P(A) = \frac{4}{52}

Prob (the left over card to be non jack ) = P(B) = \frac{48}{52}

A and B are mutually exclusive and exhaustive

Let drawing 3 Jacks be the event C

P(C) = P(AC)+P(BC)

P(AC) = P(A)*P(C/A)\\= \frac{4}{52} (3/51C3)\\=1.108(10^{-5}

P(BC) = P(B)*P(C/B)\\

= \frac{28}{52} (4/51C3)\\

=1.034(10^{-4}

Adding we get

P(C)

= (1.108+10.343)(10^{-5} \\=0.001145

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Answer:

<u></u>

  • <u>See below</u>

Explanation:

Determining the <em>domain</em> of the function P(x) = 2x + 8 is very trivial and does not require the uses of separate intervals.

The domain of a function is the set of input values (x) for which the function is defined. Thus, the domain of P(x) = 2x + 8 is all the real number, which in interval notaion is:

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In <em>interval notation</em> it is:

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