You need to simplify it
lets start with your orgininal equation here:
-5+3x=10
Now lets try and get "x" alone. we will do this by adding 5 to both sides.
-5+3x=10
+5 +5
3x=15
Now we have 3 times "x" equals 15
The next step would be to divide both sides by 3 in order to get "x" alone.
3x=15
x=15/3
x=5
What am i supposed to be anawering here? as a function of x or y? solving for x or y or simply writing in mx+b form?
<u>Rectangle A</u>
P = 2l + 2w
P = 2(3x + 2) + 2(2x - 1)
P = 2(3x) + 2(2) + 2(2x) - 2(1)
P = 6x + 4 + 4x - 2
P = 6x + 4x + 4 - 2
P = 10x + 2
<u>
Rectangle B</u>
P = 2l + 2w
P = 2(x + 5) + 2(5x - 1)
P = 2(x) + 2(5) + 2(5x) - 2(1)
P = 2x + 10 + 10x - 2
P = 2x + 10x + 10 - 2
P = 12x + 8
<u>Rectangle B - Rectangle A</u>
(12x + 8) - (10x + 2)
12x - 10x + 8 - 2
2x + 6
The correct answer is B.
Answer:
ANSWER D).
.. ![\sqrt[3]{a^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%20%7D)
Step-by-step explanation:
![x^{\frac{m}{n} } = \sqrt[n]{x^{m} }](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%20%7D)
-
= ![\sqrt[3]{a^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%20%7D)
To prove that <span>ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.
From the diagram, it is shown that CA is congruent to RM.
From the first option, given that </span>m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = <span>m∠M = 64°). </span>
This shows that the first option is correct.
From the second option, given that CB = MQ = 29 cm, then we have CA = RM, <span>CB = MQ, but ACB is not congruent to RMQ.
Thus the second option in not correct.
From the third option, </span>m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60<span>°, but we do not know the value of MRQ.
Thus the third option is not correct.
From the fourth option, </span>m∠R = 60° and AB ≅ MQ, then we have <span>CA = RM, AB = MQ, RMQ = </span>64<span>°, but we do not know the value of CAB.
Thus the fourth option is not correct.
From the fifth option</span>, <span>AB = QR = 31 cm, then we have </span><span>CA = RM, </span><span>AB = QR, but we do not know the value of CAB or MRQ.
Thus, the fifth option is not correct.
Therefore, the additional information that </span><span>could be used to prove ΔABC ≅ ΔMQR using SAS is </span><span>m∠A = 64° and AB = MQ = 31 cm</span>