Hello! And thank you for your question!
For this problem we can use the FOIL method/distributive method.
Rewrite the equation to:
(4g³) + (-1)(3g) + (-10)
Then solve:
(4g³) times (3g¹) = 12g⁴
(4g³) times (-10) = -40g³
(-1) times (3g) = -3g
(-1) times (-10) = 10
Final Answer:
12g⁴ - 40g³ - 3g + 10
Answer: $ 14
Step-by-step explanation:
Since, the cost of 1 pair of socks = x
The cost of 6 pair of socks = 6 x
Total amount spend = $ 40
According to the question,
6 x - 14 = 40
6 x = 40 + 14
6 x = 54
x = 9
Thus, the original price of one pair of socks = $ 9
⇒ The original price of 6 pairs of socks = $ 54
Hence, the total change = original price of socks - the price of socks in the sale = 54 - 40 = $ 14
Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
