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Serhud [2]
3 years ago
14

How much work will be done by electric energy source with a P.d of 4KV that delivers a current of 1 A for 1 minute?

Physics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

Given that battery V = 12.0 V

Resistance R = 2.0 ohms

a ) current in the battery is I = V /R

                                                = 12.0 V / 2.0

                                                = 6.0 A

b ) charge transported in the circuit is   q = i * t  

                                                                = 6.0 A * 10 s

                                                                 = 60 C

c ) Work done on the charge by the electric field is 0 ( there is no internal resistance )

d ) work done through the resistor is w = P * t

                                                            = ( V)^2 / R * t

                                                            = ( 12.0 V )^2 / 2 *10s

                                                             = 720J

e ) Total work done is equal to work done through the resistor

                       W_total = 720 J

f ) there is no internal resistance hence  E = 0

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A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t
BaLLatris [955]
Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

15kg * 3.50 m/s + 9kg * 2.35 m/s = 73.65 kg m/s

73.65 = 9 * 2.8 + 15x

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5 0
3 years ago
Which quantum number gives the approximate energy of an electron in the quantum mechanical model of the atom? A) n B) I C) m1 D
alexdok [17]

Answer:

Option A) n

Explanation:

In accordance to Quantum Mechanical model of an atom:

  • The Principle Quantum number (n) gives the description of the shell of an electron and the energy level of an electron in an atom.
  • The angular momentum also referred to as Azimuthal Quantum number (l) gives the description of  the shape of the orbitals and helps in determination of angular momentum magnitude.
  • The magnetic quantum number (m_{1}) describes the energy levels or the number of orbitals contained in a subshell and the way these are oriented within.
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4 0
3 years ago
During a snowball fight two balls with masses of 0.4 kg and 0.6 kg, respectively, are thrown in such a manner that they meet hea
valkas [14]
Considering conservation of momentum;
m1v1 + m2v2 = m3v3

In which,
m1 = mass of snowball 1 = 0.4 kg
v1 = velocity of snowball 1 = 15 m/s
m2 = mass of snowball 2 = 0.6 kg
v2 = velocity of snow ball 2 = 15 m/s
m3 = combined mass = 1 kg
v3 = velocity after comination
Therefore;
0.4*15 + 0.6*15 = 1*v3
v3 = 6+9 = 15 m/s
KE = 1/2mv^2

Then,
KE1 = 1/2*0.4*15^2 = 45 J
KE2 = 1/2*0.6*15^2 = 67.5 J
KE3 = 1/2*1*15^2 = 112.5 J

Therefore, KE3 (kinetic energy after collision) = K1+K2 {kinetic energy before collision). And thus it is 100%.
3 0
3 years ago
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