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zepelin [54]
3 years ago
10

Buses travel at 25 m/s then decelerate steadily. It comes to a complete stop in 40 second. What is its acceleration?

Physics
1 answer:
AnnZ [28]3 years ago
7 0
Given is the velocity of the bus at 25 meters per second. Then it decelerates steadily. It stops after 40 seconds. To calculate for the acceleration, use this formula:

a = (vf - vo) / t

vf = 0 m/s (complete stop)
vo = 25 m/s 
t = 40 s

Therefore,

a = (0 - 25) m/s / 40 s

a = - 0.625 m/s^2

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Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

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F is the force applied

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\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
1 point
RoseWind [281]

Answer:

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6 0
4 years ago
If dye x has a molar absorptivity, ε = 4.50 x 104 cm-1 m-1, at a certain wavelength, what concentration of the dye, in a 1.00 cm
NeTakaya
For this problem, the working equation should be used from the Beer's Law:

A = ∈lc,
where
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C is the concentration of the sample placed inside the cuvette

Substituting the values:

0.417 = (4.50×10⁴ cm⁻¹ M⁻¹<span>)(1 cm)(C)
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