The resistance of a conductor is given by
where L is the length of the wire,
the resistivity of the material and A the cross-sectional area.
We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length:
, then the new resistance is also 4 times the original value:
I think that may depend on the individual viewer. I'm sure most people don't even notice it. To me, it sometimes becomes nocuous.
Answer:
The average force exerted on the bullet while it is being accelerated is 6,522.52 N.
Explanation:
Given;
mass of the bullet, m = 23 g = 0.023 kg
length of the barrel, L = 62 cm = 0.62 m
speed of the bullet, v = 593 m/s
Applying work-energy theorem;
the work done in accelerating the bullet in the riffle = kinetic energy acquired by the bullet.
W = K.E
F x d = ¹/₂mv²
where;
d is the is the distance traveled by the bullet in the riffle = L
F(0.62) = ¹/₂ x 0.023 x (593²)
F(0.62) = 4043.964
F = (4043.964) / (0.62)
F = 6,522.52 N
Therefore, the average force exerted on the bullet while it is being accelerated is 6,522.52 N.
Answer:
Essentially all of it
Explanation:
The potential energy was
PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J
ignoring air resistance, this PE converts to KE
With no rebound final velocity is zero, so Kinetic energy lost = 128 J
