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oksano4ka [1.4K]
3 years ago
9

HOW MANY SECONDS ARE THERE IN 3 MONTHS OF MARCH​

Physics
1 answer:
Elanso [62]3 years ago
4 0

March has 31 days.

3 Marches have 93 days.

Each day has 86,400 seconds.

(93 days) x (86,400 sec/day) = 8,035,200 sec.

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nika2105 [10]

Answer:

<h3>C no.</h3>

Explanation:

<h2><em>M</em><em>a</em><em>r</em><em>k</em><em> </em><em>m</em><em>e</em><em> </em><em>m</em><em>e</em><em> </em><em>b</em><em>r</em><em>a</em><em>i</em><em>n</em><em>l</em><em>i</em><em>e</em><em>s</em><em>t</em><em> </em><em>p</em><em>l</em><em>z</em><em> </em><em>i</em><em> </em><em>r</em><em>e</em><em>a</em><em>l</em><em>l</em><em>y</em><em> </em><em>n</em><em>e</em><em>e</em><em>d</em><em> </em><em>i</em><em>t</em><em> </em><em>(⌒▽⌒)</em></h2>

6 0
2 years ago
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TC
frosja888 [35]

Answer:

0.08 sin 3nt +

metre. Then calculate-

a time period

(d) Time period

(

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6 0
3 years ago
Which statement is true regarding copper's ability to conduct electricity?
zhenek [66]
<span>Copper is a good conductor of electricity because its atoms have a loosely held electron in their outer shell that is able to move freely to other atoms.</span>
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Closed path that electric current follows
allochka39001 [22]
The closed path of an electric current is called the CIRCUIT.
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A thin lens with a focal length of 6.0 cm is used as a simple magnifier by (a) what angular magnification is obtainable with the
Serhud [2]

Answer:

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4.83871 cm

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Angular magnification is given by

m=\frac{25}{f}\\\Rightarrow m=\frac{25}{6}\\\Rightarrow m=4.167

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Lens equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{6}=\frac{1}{u}+\frac{1}{-25}\\\Rightarrow \frac{1}{6}+\frac{1}{25}=\frac{1}{u}\\\Rightarrow \frac{1}{u}=\frac{31}{150}\\\Rightarrow u=4.83871\ cm

The closest distance by which the object can be examined is 4.83871 cm

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