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oksano4ka [1.4K]
3 years ago
9

HOW MANY SECONDS ARE THERE IN 3 MONTHS OF MARCH​

Physics
1 answer:
Elanso [62]3 years ago
4 0

March has 31 days.

3 Marches have 93 days.

Each day has 86,400 seconds.

(93 days) x (86,400 sec/day) = 8,035,200 sec.

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Mila [183]
The answer is 0 bc she didint move
Explanation:
8 0
3 years ago
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How many straight edges does a cube have
Lunna [17]
12 is correct

Explanation: it's a cube
6 0
3 years ago
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During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to c
IRINA_888 [86]

During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to come near, the clown turns due east and runs 19.8 m to exit the arena. The magnitude of the clown’s displacement is 27 m.

<u>Explanation: </u>

As the clown is running in the north direction for about 7.7 m and then he turns 49.9 degrees east of north. In the east of north, he covers a distance of 6.4 m and then turns east to exit the arena after covering a distance of 19.8 m. Let’s have a simple diagram to easily understand the problem.

In first step, the clown runs 7.7 m in north direction, so the image will be  as in fig 1. Then he takes a direction of north east and covers a distance of 6.4 m, so the image will be modified as in fig 2. Then after the bull comes, he turns east and runs 19.8 m to exit the arena, so the image will be as in figure 3.

So, the extension of North line and the East line at a point shown as the dotted line in the above image, forms the total displacement as the hypotenuse of a right angled triangle. The extended dotted lines is nothing but the horizontal and vertical components of the angle 49.9 degree.

By using Pythagoras theorem, the total displacement can be found as

\text { Total displacement }=\sqrt{(o p p)^{2}+(a d j)^{2}}

\text { Distance covered by the clown in east direction }=(6.4 \times \cos 49.9)+19.8=23.9 \mathrm{m}

Similarly, the adjacent side of this imaginary triangle is the distance covered by the clown in the North direction.

\text { Distance covered by the clown in north direction }=6.4 \sin 49.9+7.7=12.6 \mathrm{m}

Thus, the total displacement covered by the clown is

\text { Total displacement }=\sqrt{(23.9)^{2}+(12.6)^{2}}=\sqrt{571.21+158.76}=\sqrt{729.97}=27 \mathrm{m}

Thus, the total displacement by the clown is 27 m.

5 0
3 years ago
Question in picture.
Gelneren [198K]
<h2>Hello!</h2>

The answer is: A. 19.3 joules

<h2>Why?</h2>

Since it's an elastic collision, the kinetic energy after and before the collision will be the same.

Kinetic energy can be calculated using the following equation:

KE=\frac{1}{2}mv^{2}

Where:

KE=KineticEnergy\\m=mass\\v=velocity

So,

First object, (going to the right):

m=7.20kg\\v=2\frac{m}{s}

KE_{1}=\frac{1}{2}*7.20Kg*(2\frac{m}{s})^{2}=14.4Joules

Second object:, (going to the left):

m=5.75kg\\v=-1.30\frac{m}{s}

KE_{2}=\frac{1}{2}*5.75kg*(-1.30\frac{m}{s})^{2}=4.86Joules

Remember,

1Joule=1Kg.\frac{m^{2}}{s^{2} }

Hence,

The total kinetic energy after the collision will be:

T=KE_{1}+KE_{2}=14.4Joules+4.86joules=19.26joules=19.3joules

The total kinetic energy after the collision is 19.3 joules (rounded to the nearest tenth)

Have a nice day!

6 0
3 years ago
Physics in motion Unit 6A The nature of waves
Daniel [21]

#1

length of one complete wave shape is known as wavelength

#2

Frequency is defined as number of oscillations per second or number of waves passing through a point in one second.

#3

One Time period is the time to cover one complete wavelength distance by the wave

#4

relation between time period and frequency is given as

f = \frac{1}{T}

#5

Time period of simple pendulum is given as

T = 2\pi \sqrt{\frac{L}{g}}

so it depends on length of pendulum and acceleration due to gravity

#6

amplitude of the wave is the height above the axis to which particle can attain its maximum position or its maximum height on y axis is amplitude

4 0
3 years ago
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