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Dima020 [189]
3 years ago
6

40x^-4 y^-6/(over)10x^-5 y^5

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

4x/y¹¹

Step-by-step explanation:

1) take out constants

40/10 * x⁻⁴y⁻⁶/x⁻⁵y⁵

2) simplify 40/10 to 4

4 * x⁻⁴y⁻⁶/x⁻⁵y⁵

3) Use Quotient Rule: xᵃ/xᵇ=xᵃ⁻ᵇ

4x⁻⁴⁺⁵y⁻⁶⁻⁵

4) Simplify -4 + 5 to 1

4x¹y⁻⁶⁻⁵

5) simplify -6-5 to -11

4x¹y⁻¹¹

6) use rule of one: ₓ¹=ₓ

4xy⁻¹¹

7) use negative power rule: x⁻ᵃ=1/xᵃ

4x * 1/y¹¹

8) simplify

4x/y¹¹

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3 years ago
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A) If 2 points on the rectangle are (a, b) and (c, d), then identify the two missing points on the rectangle?
balu736 [363]

Let us write vertices of the given rectangle are PQRS.

Where Q is (c,d) and S is (a,b).

a) Now, we need to find the coordinates of P and R points.

x-coordinate for P is a and y-coordinate of P is d.

<h3>Therefore P is (a,d).</h3>

On the same way, x-coordinate for R is c and y-coordinate of R is b.

<h3>Therefore R is (d,b).</h3>

b) <em>Width of the rectangle is difference of y-coordinates of P and S points</em>.

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8 0
3 years ago
A boat is marked up 20% on the original price the original price was $50 what is the sale price of the boat before sales taxes
bezimeni [28]

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42.9

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6 0
4 years ago
Find the sum of the first 20 terms of an arithmetic series if the first term is 4 and the common difference is 3.
Ratling [72]

The sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.

Step-by-step explanation:

First Term  (a) = 4

Common difference  (d) = 3

The number of term (n) = 20

The sum of an Arithmetic series of (n) number of terms, with first term (a) and the common difference (d) is equal to

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So putting the values of a,d, n

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Sum = 10 * 65 = 650

Hence the sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.

8 0
3 years ago
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