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2 years ago

40x^-4 y^-6/(over)10x^-5 y^5

Mathematics

1 answer:

lisov135 [29]2 years ago

7 0

Answer:

4x/y¹¹

Step-by-step explanation:

1) take out constants

40/10 * x⁻⁴y⁻⁶/x⁻⁵y⁵

2) simplify 40/10 to 4

4 * x⁻⁴y⁻⁶/x⁻⁵y⁵

3) Use Quotient Rule: xᵃ/xᵇ=xᵃ⁻ᵇ

4x⁻⁴⁺⁵y⁻⁶⁻⁵

4) Simplify -4 + 5 to 1

4x¹y⁻⁶⁻⁵

5) simplify -6-5 to -11

4x¹y⁻¹¹

6) use rule of one: ₓ¹=ₓ

4xy⁻¹¹

7) use negative power rule: x⁻ᵃ=1/xᵃ

4x * 1/y¹¹

8) simplify

4x/y¹¹

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If John pays $144 for 9 pounds of pears, how much is each pound

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3 years ago

Read 2 more answers

Sofia measures the length of her car as 16 feet. What is the greatest possible error? ______ feet What is the margin of error? _

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3 years ago

<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7

zhenek [66]

Answer:

Step-by-step explanation:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}$

$\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}$

$3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}$

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}$

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}$

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0

3 years ago